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nomicon/src/lifetime-mismatch.md

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# Limits of Lifetimes
Given the following code:
```rust,ignore
struct Foo;
impl Foo {
fn mutate_and_share(&mut self) -> &Self { &*self }
fn share(&self) {}
}
fn main() {
let mut foo = Foo;
let loan = foo.mutate_and_share();
foo.share();
}
```
One might expect it to compile. We call `mutate_and_share`, which mutably borrows
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`foo` temporarily, but then returns only a shared reference. Therefore we
would expect `foo.share()` to succeed as `foo` shouldn't be mutably borrowed.
However when we try to compile it:
```text
<anon>:11:5: 11:8 error: cannot borrow `foo` as immutable because it is also borrowed as mutable
<anon>:11 foo.share();
^~~
<anon>:10:16: 10:19 note: previous borrow of `foo` occurs here; the mutable borrow prevents subsequent moves, borrows, or modification of `foo` until the borrow ends
<anon>:10 let loan = foo.mutate_and_share();
^~~
<anon>:12:2: 12:2 note: previous borrow ends here
<anon>:8 fn main() {
<anon>:9 let mut foo = Foo;
<anon>:10 let loan = foo.mutate_and_share();
<anon>:11 foo.share();
<anon>:12 }
^
```
What happened? Well, we got the exact same reasoning as we did for
[Example 2 in the previous section][ex2]. We desugar the program and we get
the following:
```rust,ignore
struct Foo;
impl Foo {
fn mutate_and_share<'a>(&'a mut self) -> &'a Self { &'a *self }
fn share<'a>(&'a self) {}
}
fn main() {
'b: {
let mut foo: Foo = Foo;
'c: {
let loan: &'c Foo = Foo::mutate_and_share::<'c>(&'c mut foo);
'd: {
Foo::share::<'d>(&'d foo);
}
}
}
}
```
The lifetime system is forced to extend the `&mut foo` to have lifetime `'c`,
due to the lifetime of `loan` and mutate_and_share's signature. Then when we
try to call `share`, and it sees we're trying to alias that `&'c mut foo` and
blows up in our face!
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This program is clearly correct according to the reference semantics we actually
care about, but the lifetime system is too coarse-grained to handle that.
TODO: other common problems? SEME regions stuff, mostly?
[ex2]: lifetimes.html#example-aliasing-a-mutable-reference