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255 lines
8.1 KiB
255 lines
8.1 KiB
10 years ago
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% Data Representation in Rust
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Low-level programming cares a lot about data layout. It's a big deal. It also pervasively
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influences the rest of the language, so we're going to start by digging into how data is
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represented in Rust.
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# The `rust` repr
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Rust gives you the following ways to lay out composite data:
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* structs (named product types)
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* tuples (anonymous product types)
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* arrays (homogeneous product types)
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* enums (named sum types -- tagged unions)
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For all these, individual fields are aligned to their preferred alignment.
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For primitives this is equal to
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their size. For instance, a u32 will be aligned to a multiple of 32 bits, and a u16 will
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be aligned to a multiple of 16 bits. Composite structures will have their size rounded
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up to be a multiple of the highest alignment required by their fields, and an alignment
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requirement equal to the highest alignment required by their fields. So for instance,
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```rust
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struct A {
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a: u8,
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c: u64,
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b: u32,
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}
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```
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will have a size that is a multiple of 64-bits, and 64-bit alignment.
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There is *no indirection* for these types; all data is stored contiguously as you would
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expect in C. However with the exception of arrays, the layout of data is not by
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default specified in Rust. Given the two following struct definitions:
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```rust
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struct A {
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a: i32,
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b: u64,
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}
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struct B {
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x: i32,
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b: u64,
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}
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```
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Rust *does* guarantee that two instances of A have their data laid out in exactly
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the same way. However Rust *does not* guarantee that an instance of A has the same
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field ordering or padding as an instance of B (in practice there's no *particular*
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reason why they wouldn't, other than that its not currently guaranteed).
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With A and B as written, this is basically nonsensical, but several other features
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of Rust make it desirable for the language to play with data layout in complex ways.
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For instance, consider this struct:
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```rust
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struct Foo<T, U> {
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count: u16,
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data1: T,
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data2: U,
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}
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```
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Now consider the monomorphizations of `Foo<u32, u16>` and `Foo<u16, u32>`. If Rust lays out the
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fields in the order specified, we expect it to *pad* the values in the struct to satisfy
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their *alignment* requirements. So if Rust didn't reorder fields, we would expect Rust to
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produce the following:
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```rust
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struct Foo<u16, u32> {
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count: u16,
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data1: u16,
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data2: u32,
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}
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struct Foo<u32, u16> {
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count: u16,
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_pad1: u16,
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data1: u32,
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data2: u16,
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_pad2: u16,
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}
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```
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The former case quite simply wastes space. An optimal use of space therefore requires
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different monomorphizations to *have different field orderings*.
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**Note: this is a hypothetical optimization that is not yet implemented in Rust 1.0.0**
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Enums make this consideration even more complicated. Naively, an enum such as:
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```rust
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enum Foo {
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A(u32),
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B(u64),
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C(u8),
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}
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```
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would be laid out as:
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```rust
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struct FooRepr {
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data: u64, // this is *really* either a u64, u32, or u8 based on `tag`
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tag: u8, // 0 = A, 1 = B, 2 = C
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}
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```
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And indeed this is approximately how it would be laid out in general
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(modulo the size and position of `tag`). However there are several cases where
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such a representation is ineffiecient. The classic case of this is Rust's
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"null pointer optimization". Given a pointer that is known to not be null
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(e.g. `&u32`), an enum can *store* a discriminant bit *inside* the pointer
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by using null as a special value. The net result is that
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`sizeof(Option<&T>) == sizeof<&T>`
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There are many types in Rust that are, or contain, "not null" pointers such as `Box<T>`, `Vec<T>`,
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`String`, `&T`, and `&mut T`. Similarly, one can imagine nested enums pooling their tags into
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a single descriminant, as they are by definition known to have a limited range of valid values.
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In principle enums can use fairly elaborate algorithms to cache bits throughout nested types
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with special constrained representations. As such it is *especially* desirable that we leave
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enum layout unspecified today.
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# Dynamically Sized Types (DSTs)
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Rust also supports types without a statically known size. On the surface,
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this is a bit nonsensical: Rust must know the size of something in order to
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work with it. DSTs are generally produced as views, or through type-erasure
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of types that *do* have a known size. Due to their lack of a statically known
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size, these types can only exist *behind* some kind of pointer. They consequently
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produce a *fat* pointer consisting of the pointer and the information that
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*completes* them.
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For instance, the slice type, `[T]`, is some statically unknown number of elements
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stored contiguously. `&[T]` consequently consists of a `(&T, usize)` pair that specifies
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where the slice starts, and how many elements it contains. Similarly Trait Objects
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support interface-oriented type erasure through a `(data_ptr, vtable_ptr)` pair.
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Structs can actually store a single DST directly as their last field, but this
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makes them a DST as well:
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```rust
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// Can't be stored on the stack directly
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struct Foo {
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info: u32,
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data: [u8],
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}
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```
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# Zero Sized Types (ZSTs)
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Rust actually allows types to be specified that occupy *no* space:
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```rust
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struct Foo; // No fields = no size
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enum Bar; // No variants = no size
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// All fields have no size = no size
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struct Baz {
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foo: Foo,
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bar: Bar,
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qux: (), // empty tuple has no size
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}
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```
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On their own, ZSTs are, for obvious reasons, pretty useless. However
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as with many curious layout choices in Rust, their potential is realized in a generic
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context.
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Rust largely understands that any operation that produces or stores a ZST
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can be reduced to a no-op. For instance, a `HashSet<T>` can be effeciently implemented
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as a thin wrapper around `HashMap<T, ()>` because all the operations `HashMap` normally
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does to store and retrieve keys will be completely stripped in monomorphization.
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Similarly `Result<(), ()>` and `Option<()>` are effectively just fancy `bool`s.
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Safe code need not worry about ZSTs, but *unsafe* code must be careful about the
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consequence of types with no size. In particular, pointer offsets are no-ops, and
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standard allocators (including jemalloc, the one used by Rust) generally consider
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passing in `0` as Undefined Behaviour.
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# Drop Flags
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For unfortunate legacy implementation reasons, Rust as of 1.0.0 will do a nasty trick to
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any type that implements the `Drop` trait (has a destructor): it will insert a secret field
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in the type. That is,
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```rust
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struct Foo {
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a: u32,
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b: u32,
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}
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impl Drop for Foo {
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fn drop(&mut self) { }
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}
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```
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will cause Foo to secretly become:
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```rust
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struct Foo {
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a: u32,
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b: u32,
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_drop_flag: u8,
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}
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```
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For details as to *why* this is done, and how to make it not happen, check out
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[SOME OTHER SECTION].
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# Alternative representations
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Rust allows you to specify alternative data layout strategies from the default Rust
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one.
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# repr(C)
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This is the most important `repr`. It has fairly simple intent: do what C does.
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The order, size, and alignment of fields is exactly what you would expect from
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C or C++. Any type you expect to pass through an FFI boundary should have `repr(C)`,
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as C is the lingua-franca of the programming world. However this is also necessary
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to soundly do more elaborate tricks with data layout such as reintepretting values
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as a different type.
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However, the interaction with Rust's more exotic data layout features must be kept
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in mind. Due to its dual purpose as a "for FFI" and "for layout control", repr(C)
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can be applied to types that will be nonsensical or problematic if passed through
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the FFI boundary.
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* ZSTs are still zero-sized, even though this is not a standard behaviour
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in C, and is explicitly contrary to the behaviour of an empty type in C++, which
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still consumes a byte of space.
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* DSTs are not a concept in C
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* **The drop flag will still be added**
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* This is equivalent to repr(u32) for enums (see below)
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# repr(packed)
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`repr(packed)` forces rust to strip any padding it would normally apply.
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This may improve the memory footprint of a type, but will have negative
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side-effects from "field access is heavily penalized" to "completely breaks
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everything" based on target platform.
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# repr(u8), repr(u16), repr(u32), repr(u64)
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These specify the size to make a c-like enum (one which has no values in its variants).
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