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% Unchecked Uninitialized Memory
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One interesting exception to this rule is working with arrays. Safe Rust doesn't
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permit you to partially initialize an array. When you initialize an array, you
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can either set every value to the same thing with `let x = [val; N]`, or you can
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specify each member individually with `let x = [val1, val2, val3]`.
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Unfortunately this is pretty rigid, especially if you need to initialize your
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array in a more incremental or dynamic way.
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Unsafe Rust gives us a powerful tool to handle this problem:
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`mem::uninitialized`. This function pretends to return a value when really
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it does nothing at all. Using it, we can convince Rust that we have initialized
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a variable, allowing us to do trickier things with conditional and incremental
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initialization.
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Unfortunately, this opens us up to all kinds of problems. Assignment has a
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different meaning to Rust based on whether it believes that a variable is
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initialized or not. If it's believed uninitialized, then Rust will semantically
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just memcopy the bits over the uninitialized ones, and do nothing else. However
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if Rust believes a value to be initialized, it will try to `Drop` the old value!
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Since we've tricked Rust into believing that the value is initialized, we can no
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longer safely use normal assignment.
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This is also a problem if you're working with a raw system allocator, which
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returns a pointer to uninitialized memory.
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To handle this, we must use the `ptr` module. In particular, it provides
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three functions that allow us to assign bytes to a location in memory without
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dropping the old value: `write`, `copy`, and `copy_nonoverlapping`.
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* `ptr::write(ptr, val)` takes a `val` and moves it into the address pointed
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to by `ptr`.
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* `ptr::copy(src, dest, count)` copies the bits that `count` T's would occupy
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from src to dest. (this is equivalent to memmove -- note that the argument
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order is reversed!)
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* `ptr::copy_nonoverlapping(src, dest, count)` does what `copy` does, but a
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little faster on the assumption that the two ranges of memory don't overlap.
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(this is equivalent to memcpy -- note that the argument order is reversed!)
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It should go without saying that these functions, if misused, will cause serious
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havoc or just straight up Undefined Behavior. The only things that these
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functions *themselves* require is that the locations you want to read and write
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are allocated. However the ways writing arbitrary bits to arbitrary
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locations of memory can break things are basically uncountable!
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Putting this all together, we get the following:
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```rust
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use std::mem;
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use std::ptr;
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// size of the array is hard-coded but easy to change. This means we can't
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// use [a, b, c] syntax to initialize the array, though!
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const SIZE: usize = 10;
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let mut x: [Box<u32>; SIZE];
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unsafe {
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// convince Rust that x is Totally Initialized
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x = mem::uninitialized();
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for i in 0..SIZE {
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// very carefully overwrite each index without reading it
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// NOTE: exception safety is not a concern; Box can't panic
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ptr::write(&mut x[i], Box::new(i as u32));
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}
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}
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println!("{:?}", x);
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```
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It's worth noting that you don't need to worry about `ptr::write`-style
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shenanigans with types which don't implement `Drop` or contain `Drop` types,
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because Rust knows not to try to drop them. Similarly you should be able to
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assign to fields of partially initialized structs directly if those fields don't
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contain any `Drop` types.
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However when working with uninitialized memory you need to be ever-vigilant for
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Rust trying to drop values you make like this before they're fully initialized.
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Every control path through that variable's scope must initialize the value
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before it ends, if it has a destructor.
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*[This includes code panicking](unwinding.html)*.
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And that's about it for working with uninitialized memory! Basically nothing
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anywhere expects to be handed uninitialized memory, so if you're going to pass
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it around at all, be sure to be *really* careful.
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