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<main>
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<h1 id="cell-和-refcell"><a class="header" href="#cell-和-refcell">Cell 和 RefCell</a></h1>
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<p>Rust 的编译器之严格,可以说是举世无双。特别是在所有权方面,Rust 通过严格的规则来保证所有权和借用的正确性,最终为程序的安全保驾护航。</p>
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<p>但是严格是一把双刃剑,带来安全提升的同时,损失了灵活性,有时甚至会让用户痛苦不堪、怨声载道。因此 Rust 提供了 <code>Cell</code> 和 <code>RefCell</code> 用于内部可变性,简而言之,可以在拥有不可变引用的同时修改目标数据,对于正常的代码实现来说,这个是不可能做到的(要么一个可变借用,要么多个不可变借用)。</p>
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<blockquote>
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|
<p>内部可变性的实现是因为 Rust 使用了 <code>unsafe</code> 来做到这一点,但是对于使用者来说,这些都是透明的,因为这些不安全代码都被封装到了安全的 API 中</p>
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</blockquote>
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<h2 id="cell"><a class="header" href="#cell">Cell</a></h2>
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<p><code>Cell</code> 和 <code>RefCell</code> 在功能上没有区别,区别在于 <code>Cell<T></code> 适用于 <code>T</code> 实现 <code>Copy</code> 的情况:</p>
|
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<pre class="playground"><code class="language-rust edition2021">use std::cell::Cell;
|
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|
fn main() {
|
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let c = Cell::new("asdf");
|
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let one = c.get();
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c.set("qwer");
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let two = c.get();
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println!("{},{}", one, two);
|
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}</code></pre>
|
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<p>以上代码展示了 <code>Cell</code> 的基本用法,有几点值得注意:</p>
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<ul>
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|
|
<li>“asdf” 是 <code>&str</code> 类型,它实现了 <code>Copy</code> 特征</li>
|
|
|
<li><code>c.get</code> 用来取值,<code>c.set</code> 用来设置新值</li>
|
|
|
</ul>
|
|
|
<p>取到值保存在 <code>one</code> 变量后,还能同时进行修改,这个违背了 Rust 的借用规则,但是由于 <code>Cell</code> 的存在,我们很优雅地做到了这一点,但是如果你尝试在 <code>Cell</code> 中存放<code>String</code>:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2021"><span class="boring">#![allow(unused)]
|
|
|
</span><span class="boring">fn main() {
|
|
|
</span> let c = Cell::new(String::from("asdf"));
|
|
|
<span class="boring">}</span></code></pre>
|
|
|
<p>编译器会立刻报错,因为 <code>String</code> 没有实现 <code>Copy</code> 特征:</p>
|
|
|
<pre><code class="language-console">| pub struct String {
|
|
|
| ----------------- doesn't satisfy `String: Copy`
|
|
|
|
|
|
|
= note: the following trait bounds were not satisfied:
|
|
|
`String: Copy`
|
|
|
</code></pre>
|
|
|
<h2 id="refcell"><a class="header" href="#refcell">RefCell</a></h2>
|
|
|
<p>由于 <code>Cell</code> 类型针对的是实现了 <code>Copy</code> 特征的值类型,因此在实际开发中,<code>Cell</code> 使用的并不多,因为我们要解决的往往是可变、不可变引用共存导致的问题,此时就需要借助于 <code>RefCell</code> 来达成目的。</p>
|
|
|
<p>我们可以将所有权、借用规则与这些智能指针做一个对比:</p>
|
|
|
<div class="table-wrapper">
|
|
|
<table>
|
|
|
<thead>
|
|
|
<tr><th>Rust 规则</th><th>智能指针带来的额外规则</th></tr>
|
|
|
</thead>
|
|
|
<tbody>
|
|
|
<tr><td>一个数据只有一个所有者</td><td><code>Rc/Arc</code>让一个数据可以拥有多个所有者</td></tr>
|
|
|
<tr><td>要么多个不可变借用,要么一个可变借用</td><td><code>RefCell</code>实现编译期可变、不可变引用共存</td></tr>
|
|
|
<tr><td>违背规则导致<strong>编译错误</strong></td><td>违背规则导致<strong>运行时<code>panic</code></strong></td></tr>
|
|
|
</tbody>
|
|
|
</table>
|
|
|
</div>
|
|
|
<p>可以看出,<code>Rc/Arc</code> 和 <code>RefCell</code> 合在一起,解决了 Rust 中严苛的所有权和借用规则带来的某些场景下难使用的问题。但是它们并不是银弹,例如 <code>RefCell</code> 实际上并没有解决可变引用和引用可以共存的问题,只是将报错从编译期推迟到运行时,从编译器错误变成了 <code>panic</code> 异常:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2021">use std::cell::RefCell;
|
|
|
|
|
|
fn main() {
|
|
|
let s = RefCell::new(String::from("hello, world"));
|
|
|
let s1 = s.borrow();
|
|
|
let s2 = s.borrow_mut();
|
|
|
|
|
|
println!("{},{}", s1, s2);
|
|
|
}</code></pre>
|
|
|
<p>上面代码在编译期不会报任何错误,你可以顺利运行程序:</p>
|
|
|
<pre><code class="language-console">thread 'main' panicked at 'already borrowed: BorrowMutError', src/main.rs:6:16
|
|
|
note: run with `RUST_BACKTRACE=1` environment variable to display a backtrace
|
|
|
</code></pre>
|
|
|
<p>但是依然会因为违背了借用规则导致了运行期 <code>panic</code>,这非常像中国的天网,它也许会被罪犯蒙蔽一时,但是并不会被蒙蔽一世,任何导致安全风险的存在都将不能被容忍,法网恢恢,疏而不漏。</p>
|
|
|
<h4 id="refcell-为何存在"><a class="header" href="#refcell-为何存在">RefCell 为何存在</a></h4>
|
|
|
<p>相信肯定有读者有疑问了,这么做有任何意义吗?还不如在编译期报错,至少能提前发现问题,而且性能还更好。</p>
|
|
|
<p>存在即合理,究其根因,在于 Rust 编译期的<strong>宁可错杀,绝不放过</strong>的原则,当编译器不能确定你的代码是否正确时,就统统会判定为错误,因此难免会导致一些误报。</p>
|
|
|
<p>而 <code>RefCell</code> 正是<strong>用于你确信代码是正确的,而编译器却发生了误判时</strong>。</p>
|
|
|
<p>对于大型的复杂程序,也可以选择使用 <code>RefCell</code> 来让事情简化。例如在 Rust 编译器的<a href="https://github.com/rust-lang/rust/blob/620d1ee5346bee10ba7ce129b2e20d6e59f0377d/src/librustc/middle/ty.rs#L803-L987"><code>ctxt结构体</code></a>中有大量的 <code>RefCell</code> 类型的 <code>map</code> 字段,主要的原因是:这些 <code>map</code> 会被分散在各个地方的代码片段所广泛使用或修改。由于这种分散在各处的使用方式,导致了管理可变和不可变成为一件非常复杂的任务(甚至不可能),你很容易就碰到编译器抛出来的各种错误。而且 <code>RefCell</code> 的运行时错误在这种情况下也变得非常可爱:一旦有人做了不正确的使用,代码会 <code>panic</code>,然后告诉我们哪些借用冲突了。</p>
|
|
|
<p>总之,当你确信编译器误报但不知道该如何解决时,或者你有一个引用类型,需要被四处使用和修改然后导致借用关系难以管理时,都可以优先考虑使用 <code>RefCell</code>。</p>
|
|
|
<h4 id="refcell-简单总结"><a class="header" href="#refcell-简单总结">RefCell 简单总结</a></h4>
|
|
|
<ul>
|
|
|
<li>与 <code>Cell</code> 用于可 <code>Copy</code> 的值不同,<code>RefCell</code> 用于引用</li>
|
|
|
<li><code>RefCell</code> 只是将借用规则从编译期推迟到程序运行期,并不能帮你绕过这个规则</li>
|
|
|
<li><code>RefCell</code> 适用于编译期误报或者一个引用被在多处代码使用、修改以至于难于管理借用关系时</li>
|
|
|
<li>使用 <code>RefCell</code> 时,违背借用规则会导致运行期的 <code>panic</code></li>
|
|
|
</ul>
|
|
|
<h2 id="选择-cell-还是-refcell"><a class="header" href="#选择-cell-还是-refcell">选择 <code>Cell</code> 还是 <code>RefCell</code></a></h2>
|
|
|
<p>根据本文的内容,我们可以大概总结下两者的区别:</p>
|
|
|
<ul>
|
|
|
<li><code>Cell</code> 只适用于 <code>Copy</code> 类型,用于提供值,而 <code>RefCell</code> 用于提供引用</li>
|
|
|
<li><code>Cell</code> 不会 <code>panic</code>,而 <code>RefCell</code> 会</li>
|
|
|
</ul>
|
|
|
<h4 id="性能比较"><a class="header" href="#性能比较">性能比较</a></h4>
|
|
|
<p><code>Cell</code> 没有额外的性能损耗,例如以下两段代码的性能其实是一致的:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2021"><span class="boring">#![allow(unused)]
|
|
|
</span><span class="boring">fn main() {
|
|
|
</span>// code snipet 1
|
|
|
let x = Cell::new(1);
|
|
|
let y = &x;
|
|
|
let z = &x;
|
|
|
x.set(2);
|
|
|
y.set(3);
|
|
|
z.set(4);
|
|
|
println!("{}", x.get());
|
|
|
|
|
|
// code snipet 2
|
|
|
let mut x = 1;
|
|
|
let y = &mut x;
|
|
|
let z = &mut x;
|
|
|
x = 2;
|
|
|
*y = 3;
|
|
|
*z = 4;
|
|
|
println!("{}", x);
|
|
|
<span class="boring">}</span></code></pre>
|
|
|
<p>虽然性能一致,但代码 <code>1</code> 拥有代码 <code>2</code> 不具有的优势:它能编译成功:)</p>
|
|
|
<p>与 <code>Cell</code> 的 <code>zero cost</code> 不同,<code>RefCell</code> 其实是有一点运行期开销的,原因是它包含了一个字节大小的“借用状态”指示器,该指示器在每次运行时借用时都会被修改,进而产生一点开销。</p>
|
|
|
<p>总之,当非要使用内部可变性时,首选 <code>Cell</code>,只有你的类型没有实现 <code>Copy</code> 时,才去选择 <code>RefCell</code>。</p>
|
|
|
<h2 id="内部可变性"><a class="header" href="#内部可变性">内部可变性</a></h2>
|
|
|
<p>之前我们提到 <code>RefCell</code> 具有内部可变性,何为内部可变性?简单来说,对一个不可变的值进行可变借用,但这个并不符合 Rust 的基本借用规则:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2021">fn main() {
|
|
|
let x = 5;
|
|
|
let y = &mut x;
|
|
|
}</code></pre>
|
|
|
<p>上面的代码会报错,因为我们不能对一个不可变的值进行可变借用,这会破坏 Rust 的安全性保证,相反,你可以对一个可变值进行不可变借用。原因是:当值不可变时,可能会有多个不可变的引用指向它,此时若将其中一个修改为可变的,会造成可变引用与不可变引用共存的情况;而当值可变时,最多只会有一个可变引用指向它,将其修改为不可变,那么最终依然是只有一个不可变的引用指向它。</p>
|
|
|
<p>虽然基本借用规则是 Rust 的基石,然而在某些场景中,一个值可以在其方法内部被修改,同时对于其它代码不可变,是很有用的:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2021"><span class="boring">#![allow(unused)]
|
|
|
</span><span class="boring">fn main() {
|
|
|
</span>// 定义在外部库中的特征
|
|
|
pub trait Messenger {
|
|
|
fn send(&self, msg: String);
|
|
|
}
|
|
|
|
|
|
// --------------------------
|
|
|
// 我们的代码中的数据结构和实现
|
|
|
struct MsgQueue {
|
|
|
msg_cache: Vec<String>,
|
|
|
}
|
|
|
|
|
|
impl Messenger for MsgQueue {
|
|
|
fn send(&self, msg: String) {
|
|
|
self.msg_cache.push(msg)
|
|
|
}
|
|
|
}
|
|
|
<span class="boring">}</span></code></pre>
|
|
|
<p>如上所示,外部库中定义了一个消息发送器特征 <code>Messenger</code>,它只有一个发送消息的功能:<code>fn send(&self, msg: String)</code>,因为发送消息不需要修改自身,因此原作者在定义时,使用了 <code>&self</code> 的不可变借用,这个无可厚非。</p>
|
|
|
<p>我们要在自己的代码中使用该特征实现一个异步消息队列,出于性能的考虑,消息先写到本地缓存(内存)中,然后批量发送出去,因此在 <code>send</code> 方法中,需要将消息先行插入到本地缓存 <code>msg_cache</code> 中。但是问题来了,该 <code>send</code> 方法的签名是 <code>&self</code>,因此上述代码会报错:</p>
|
|
|
<pre><code class="language-console">error[E0596]: cannot borrow `self.msg_cache` as mutable, as it is behind a `&` reference
|
|
|
--> src/main.rs:11:9
|
|
|
|
|
|
|
2 | fn send(&self, msg: String);
|
|
|
| ----- help: consider changing that to be a mutable reference: `&mut self`
|
|
|
...
|
|
|
11 | self.msg_cache.push(msg)
|
|
|
| ^^^^^^^^^^^^^^^^^^ `self` is a `&` reference, so the data it refers to cannot be borrowed as mutable
|
|
|
</code></pre>
|
|
|
<p>在报错的同时,编译器大聪明还善意地给出了提示:将 <code>&self</code> 修改为 <code>&mut self</code>,但是。。。我们实现的特征是定义在外部库中,因此该签名根本不能修改。值此危急关头, <code>RefCell</code> 闪亮登场:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2021">use std::cell::RefCell;
|
|
|
pub trait Messenger {
|
|
|
fn send(&self, msg: String);
|
|
|
}
|
|
|
|
|
|
pub struct MsgQueue {
|
|
|
msg_cache: RefCell<Vec<String>>,
|
|
|
}
|
|
|
|
|
|
impl Messenger for MsgQueue {
|
|
|
fn send(&self, msg: String) {
|
|
|
self.msg_cache.borrow_mut().push(msg)
|
|
|
}
|
|
|
}
|
|
|
|
|
|
fn main() {
|
|
|
let mq = MsgQueue {
|
|
|
msg_cache: RefCell::new(Vec::new()),
|
|
|
};
|
|
|
mq.send("hello, world".to_string());
|
|
|
}</code></pre>
|
|
|
<p>这个 MQ 功能很弱,但是并不妨碍我们演示内部可变性的核心用法:通过包裹一层 <code>RefCell</code>,成功的让 <code>&self</code> 中的 <code>msg_cache</code> 成为一个可变值,然后实现对其的修改。</p>
|
|
|
<h2 id="rc--refcell-组合使用"><a class="header" href="#rc--refcell-组合使用">Rc + RefCell 组合使用</a></h2>
|
|
|
<p>在 Rust 中,一个常见的组合就是 <code>Rc</code> 和 <code>RefCell</code> 在一起使用,前者可以实现一个数据拥有多个所有者,后者可以实现数据的可变性:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2021">use std::cell::RefCell;
|
|
|
use std::rc::Rc;
|
|
|
fn main() {
|
|
|
let s = Rc::new(RefCell::new("我很善变,还拥有多个主人".to_string()));
|
|
|
|
|
|
let s1 = s.clone();
|
|
|
let s2 = s.clone();
|
|
|
// let mut s2 = s.borrow_mut();
|
|
|
s2.borrow_mut().push_str(", oh yeah!");
|
|
|
|
|
|
println!("{:?}\n{:?}\n{:?}", s, s1, s2);
|
|
|
}
|
|
|
</code></pre>
|
|
|
<p>上面代码中,我们使用 <code>RefCell<String></code> 包裹一个字符串,同时通过 <code>Rc</code> 创建了它的三个所有者:<code>s</code>、<code>s1</code>和<code>s2</code>,并且通过其中一个所有者 <code>s2</code> 对字符串内容进行了修改。</p>
|
|
|
<p>由于 <code>Rc</code> 的所有者们共享同一个底层的数据,因此当一个所有者修改了数据时,会导致全部所有者持有的数据都发生了变化。</p>
|
|
|
<p>程序的运行结果也在预料之中:</p>
|
|
|
<pre><code class="language-console">RefCell { value: "我很善变,还拥有多个主人, oh yeah!" }
|
|
|
RefCell { value: "我很善变,还拥有多个主人, oh yeah!" }
|
|
|
RefCell { value: "我很善变,还拥有多个主人, oh yeah!" }
|
|
|
</code></pre>
|
|
|
<h4 id="性能损耗"><a class="header" href="#性能损耗">性能损耗</a></h4>
|
|
|
<p>相信这两者组合在一起使用时,很多人会好奇到底性能如何,下面我们来简单分析下。</p>
|
|
|
<p>首先给出一个大概的结论,这两者结合在一起使用的性能其实非常高,大致相当于没有线程安全版本的 C++ <code>std::shared_ptr</code> 指针,事实上,C++ 这个指针的主要开销也在于原子性这个并发原语上,毕竟线程安全在哪个语言中开销都不小。</p>
|
|
|
<h4 id="内存损耗"><a class="header" href="#内存损耗">内存损耗</a></h4>
|
|
|
<p>两者结合的数据结构与下面类似:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2021"><span class="boring">#![allow(unused)]
|
|
|
</span><span class="boring">fn main() {
|
|
|
</span>struct Wrapper<T> {
|
|
|
// Rc
|
|
|
strong_count: usize,
|
|
|
weak_count: usize,
|
|
|
|
|
|
// Refcell
|
|
|
borrow_count: isize,
|
|
|
|
|
|
// 包裹的数据
|
|
|
item: T,
|
|
|
}
|
|
|
<span class="boring">}</span></code></pre>
|
|
|
<p>从上面可以看出,从对内存的影响来看,仅仅多分配了三个<code>usize/isize</code>,并没有其它额外的负担。</p>
|
|
|
<h4 id="cpu-损耗"><a class="header" href="#cpu-损耗">CPU 损耗</a></h4>
|
|
|
<p>从 CPU 来看,损耗如下:</p>
|
|
|
<ul>
|
|
|
<li>对 <code>Rc<T></code> 解引用是免费的(编译期),但是 <code>*</code> 带来的间接取值并不免费</li>
|
|
|
<li>克隆 <code>Rc<T></code> 需要将当前的引用计数跟 <code>0</code> 和 <code>usize::Max</code> 进行一次比较,然后将计数值加 1</li>
|
|
|
<li>释放(drop) <code>Rc<T></code> 需要将计数值减 1, 然后跟 <code>0</code> 进行一次比较</li>
|
|
|
<li>对 <code>RefCell</code> 进行不可变借用,需要将 <code>isize</code> 类型的借用计数加 1,然后跟 <code>0</code> 进行比较</li>
|
|
|
<li>对 <code>RefCell </code>的不可变借用进行释放,需要将 <code>isize</code> 减 1</li>
|
|
|
<li>对 <code>RefCell</code> 的可变借用大致流程跟上面差不多,但是需要先跟 <code>0</code> 比较,然后再减 1</li>
|
|
|
<li>对 <code>RefCell</code> 的可变借用进行释放,需要将 <code>isize</code> 加 1</li>
|
|
|
</ul>
|
|
|
<p>其实这些细节不必过于关注,只要知道 CPU 消耗也非常低,甚至编译器还会对此进行进一步优化!</p>
|
|
|
<h4 id="cpu-缓存-miss"><a class="header" href="#cpu-缓存-miss">CPU 缓存 Miss</a></h4>
|
|
|
<p>唯一需要担心的可能就是这种组合数据结构对于 CPU 缓存是否亲和,这个我们无法证明,只能提出来存在这个可能性,最终的性能影响还需要在实际场景中进行测试。</p>
|
|
|
<p>总之,分析这两者组合的性能还挺复杂的,大概总结下:</p>
|
|
|
<ul>
|
|
|
<li>从表面来看,它们带来的内存和 CPU 损耗都不大</li>
|
|
|
<li>但是由于 <code>Rc</code> 额外的引入了一次间接取值(<code>*</code>),在少数场景下可能会造成性能上的显著损失</li>
|
|
|
<li>CPU 缓存可能也不够亲和</li>
|
|
|
</ul>
|
|
|
<h2 id="通过-cellfrom_mut-解决借用冲突"><a class="header" href="#通过-cellfrom_mut-解决借用冲突">通过 <code>Cell::from_mut</code> 解决借用冲突</a></h2>
|
|
|
<p>在 Rust 1.37 版本中新增了两个非常实用的方法:</p>
|
|
|
<ul>
|
|
|
<li>Cell::from_mut,该方法将 <code>&mut T</code> 转为 <code>&Cell<T></code></li>
|
|
|
<li>Cell::as_slice_of_cells,该方法将 <code>&Cell<[T]></code> 转为 <code>&[Cell<T>]</code></li>
|
|
|
</ul>
|
|
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<p>这里我们不做深入的介绍,但是来看看如何使用这两个方法来解决一个常见的借用冲突问题:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2021"><span class="boring">#![allow(unused)]
|
|
|
</span><span class="boring">fn main() {
|
|
|
</span>fn is_even(i: i32) -> bool {
|
|
|
i % 2 == 0
|
|
|
}
|
|
|
|
|
|
fn retain_even(nums: &mut Vec<i32>) {
|
|
|
let mut i = 0;
|
|
|
for num in nums.iter().filter(|&num| is_even(*num)) {
|
|
|
nums[i] = *num;
|
|
|
i += 1;
|
|
|
}
|
|
|
nums.truncate(i);
|
|
|
}
|
|
|
<span class="boring">}</span></code></pre>
|
|
|
<p>以上代码会报错:</p>
|
|
|
<pre><code class="language-console">error[E0502]: cannot borrow `*nums` as mutable because it is also borrowed as immutable
|
|
|
--> src/main.rs:8:9
|
|
|
|
|
|
|
7 | for num in nums.iter().filter(|&num| is_even(*num)) {
|
|
|
| ----------------------------------------
|
|
|
| |
|
|
|
| immutable borrow occurs here
|
|
|
| immutable borrow later used here
|
|
|
8 | nums[i] = *num;
|
|
|
| ^^^^ mutable borrow occurs here
|
|
|
</code></pre>
|
|
|
<p>很明显,报错是因为同时借用了不可变与可变引用,你可以通过索引的方式来避免这个问题:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2021"><span class="boring">#![allow(unused)]
|
|
|
</span><span class="boring">fn main() {
|
|
|
</span>fn retain_even(nums: &mut Vec<i32>) {
|
|
|
let mut i = 0;
|
|
|
for j in 0..nums.len() {
|
|
|
if is_even(nums[j]) {
|
|
|
nums[i] = nums[j];
|
|
|
i += 1;
|
|
|
}
|
|
|
}
|
|
|
nums.truncate(i);
|
|
|
}
|
|
|
<span class="boring">}</span></code></pre>
|
|
|
<p>但是这样就违背我们的初衷了,毕竟迭代器会让代码更加简洁,那么还有其它的办法吗?</p>
|
|
|
<p>这时就可以使用 <code>Cell</code> 新增的这两个方法:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2021"><span class="boring">#![allow(unused)]
|
|
|
</span><span class="boring">fn main() {
|
|
|
</span>use std::cell::Cell;
|
|
|
|
|
|
fn retain_even(nums: &mut Vec<i32>) {
|
|
|
let slice: &[Cell<i32>] = Cell::from_mut(&mut nums[..])
|
|
|
.as_slice_of_cells();
|
|
|
|
|
|
let mut i = 0;
|
|
|
for num in slice.iter().filter(|num| is_even(num.get())) {
|
|
|
slice[i].set(num.get());
|
|
|
i += 1;
|
|
|
}
|
|
|
|
|
|
nums.truncate(i);
|
|
|
}
|
|
|
<span class="boring">}</span></code></pre>
|
|
|
<p>此时代码将不会报错,因为 <code>Cell</code> 上的 <code>set</code> 方法获取的是不可变引用 <code>pub fn set(&self, val: T)</code>。</p>
|
|
|
<p>当然,以上代码的本质还是对 <code>Cell</code> 的运用,只不过这两个方法可以很方便的帮我们把 <code>&mut [T]</code> 类型转换成 <code>&[Cell<T>]</code> 类型。</p>
|
|
|
<h2 id="总结"><a class="header" href="#总结">总结</a></h2>
|
|
|
<p><code>Cell</code> 和 <code>RefCell</code> 都为我们带来了内部可变性这个重要特性,同时还将借用规则的检查从编译期推迟到运行期,但是这个检查并不能被绕过,该来早晚还是会来,<code>RefCell</code> 在运行期的报错会造成 <code>panic</code>。</p>
|
|
|
<p><code>RefCell</code> 适用于编译器误报或者一个引用被在多个代码中使用、修改以至于难于管理借用关系时,还有就是需要内部可变性时。</p>
|
|
|
<p>从性能上看,<code>RefCell</code> 由于是非线程安全的,因此无需保证原子性,性能虽然有一点损耗,但是依然非常好,而 <code>Cell</code> 则完全不存在任何额外的性能损耗。</p>
|
|
|
<p><code>Rc</code> 跟 <code>RefCell</code> 结合使用可以实现多个所有者共享同一份数据,非常好用,但是潜在的性能损耗也要考虑进去,建议对于热点代码使用时,做好 <code>benchmark</code>。</p>
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