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<h2 id="match-控制流结构"><a class="header" href="#match-控制流结构"><code>match</code> 控制流结构</a></h2>
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<!-- https://github.com/rust-lang/book/blob/main/src/ch06-02-match.md -->
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<!-- commit 5d22a358fb2380aa3f270d7b6269b67b8e44849e -->
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<p>Rust 有一个叫做 <code>match</code> 的极为强大的控制流运算符,它允许我们将一个值与一系列的模式相比较,并根据相匹配的模式执行相应代码。模式可由字面值、变量、通配符和许多其他内容构成;<a href="ch19-00-patterns.html">第十九章</a>会涉及到所有不同种类的模式以及它们的作用。<code>match</code> 的力量来源于模式的表现力,以及编译器能够确认所有可能情况均已被覆盖。</p>
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<p>可以把 <code>match</code> 表达式想象成某种硬币分类器:硬币滑入有着不同大小孔洞的轨道,每一个硬币都会掉入符合它大小的孔洞。同样地,值也会通过 <code>match</code> 的每一个模式,并且在遇到第一个 “符合” 的模式时,值会进入相关联的代码块并在执行中被使用。</p>
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<p>因为刚刚提到了硬币,让我们用它们来作为一个使用 <code>match</code> 的例子!我们可以编写一个函数来获取一个未知的美国硬币,并以一种类似验钞机的方式,确定它是何种硬币并返回它的美分值,如示例 6-3 中所示。</p>
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<pre class="playground"><code class="language-rust edition2024">enum Coin {
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Penny,
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Nickel,
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Dime,
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Quarter,
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}
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fn value_in_cents(coin: Coin) -> u8 {
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match coin {
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Coin::Penny => 1,
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Coin::Nickel => 5,
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Coin::Dime => 10,
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Coin::Quarter => 25,
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}
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}
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<span class="boring">
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</span><span class="boring">fn main() {}</span></code></pre>
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<p><span class="caption">示例 6-3:一个枚举和一个以枚举变体作为模式的 <code>match</code> 表达式</span></p>
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<p>拆开 <code>value_in_cents</code> 函数中的 <code>match</code> 来看。首先,我们列出 <code>match</code> 关键字后跟一个表达式,在这个例子中是 <code>coin</code> 的值。这看起来非常像 <code>if</code> 所使用的条件表达式,不过这里有一个非常大的区别:对于 <code>if</code>,表达式必须返回一个布尔值,而这里它可以是任何类型的。例子中的 <code>coin</code> 的类型是示例 6-3 中定义的 <code>Coin</code> 枚举。</p>
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<p>接下来是 <code>match</code> 的分支。一个分支有两个部分:一个模式和一些代码。第一个分支的模式是值 <code>Coin::Penny</code> 而之后的 <code>=></code> 运算符将模式和将要运行的代码分开。这里的代码就仅仅是值 <code>1</code>。每一个分支之间使用逗号分隔。</p>
|
|
|
<p>当 <code>match</code> 表达式执行时,它将结果值按顺序与每一个分支的模式相比较。如果模式匹配了这个值,这个模式相关联的代码将被执行。如果模式并不匹配这个值,将继续执行下一个分支,非常类似一个硬币分类器。可以拥有任意多的分支:示例 6-3 中的 <code>match</code> 有四个分支。</p>
|
|
|
<p>每个分支相关联的代码是一个表达式,而表达式的结果值将作为整个 <code>match</code> 表达式的返回值。</p>
|
|
|
<p>如果分支代码较短的话通常不使用大括号,正如示例 6-3 中的每个分支都只是返回一个值。如果想要在分支中运行多行代码,可以使用大括号,而分支后的逗号是可选的。例如,如下代码在每次使用<code>Coin::Penny</code> 调用时都会打印出 “Lucky penny!”,同时仍然返回代码块最后的值,<code>1</code>:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2024"><span class="boring">enum Coin {
|
|
|
</span><span class="boring"> Penny,
|
|
|
</span><span class="boring"> Nickel,
|
|
|
</span><span class="boring"> Dime,
|
|
|
</span><span class="boring"> Quarter,
|
|
|
</span><span class="boring">}
|
|
|
</span><span class="boring">
|
|
|
</span>fn value_in_cents(coin: Coin) -> u8 {
|
|
|
match coin {
|
|
|
Coin::Penny => {
|
|
|
println!("Lucky penny!");
|
|
|
1
|
|
|
}
|
|
|
Coin::Nickel => 5,
|
|
|
Coin::Dime => 10,
|
|
|
Coin::Quarter => 25,
|
|
|
}
|
|
|
}
|
|
|
<span class="boring">
|
|
|
</span><span class="boring">fn main() {}</span></code></pre>
|
|
|
<h3 id="绑定值的模式"><a class="header" href="#绑定值的模式">绑定值的模式</a></h3>
|
|
|
<p>匹配分支的另一个有用的功能是可以绑定匹配的模式的部分值。这也就是如何从枚举变体中提取值的。</p>
|
|
|
<p>作为一个例子,让我们修改枚举的一个变体来存放数据。1999 年到 2008 年间,美国在 25 美分的硬币的一侧为 50 个州的每一个都印刷了不同的设计。其他的硬币都没有这种区分州的设计,所以只有这些 25 美分硬币有特殊的价值。可以将这些信息加入我们的 <code>enum</code>,通过改变 <code>Quarter</code> 变体来包含一个 <code>State</code> 值,示例 6-4 中完成了这些修改:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2024">#[derive(Debug)] // 这样可以立刻看到州的名称
|
|
|
enum UsState {
|
|
|
Alabama,
|
|
|
Alaska,
|
|
|
// --snip--
|
|
|
}
|
|
|
|
|
|
enum Coin {
|
|
|
Penny,
|
|
|
Nickel,
|
|
|
Dime,
|
|
|
Quarter(UsState),
|
|
|
}
|
|
|
<span class="boring">
|
|
|
</span><span class="boring">fn main() {}</span></code></pre>
|
|
|
<p><span class="caption">示例 6-4:<code>Quarter</code> 变体也存放了一个 <code>UsState</code> 值的 <code>Coin</code> 枚举</span></p>
|
|
|
<p>想象一下我们的一个朋友尝试收集所有 50 个州的 25 美分硬币。在根据硬币类型分类零钱的同时,也可以报告出每个 25 美分硬币所对应的州名称,这样如果我们的朋友没有的话,他可以将其加入收藏。</p>
|
|
|
<p>在这些代码的匹配表达式中,我们在匹配 <code>Coin::Quarter</code> 变体的分支的模式中增加了一个叫做 <code>state</code> 的变量。当匹配到 <code>Coin::Quarter</code> 时,变量 <code>state</code> 将会绑定 25 美分硬币所对应州的值。接着在那个分支的代码中使用 <code>state</code>,如下:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2024"><span class="boring">#[derive(Debug)]
|
|
|
</span><span class="boring">enum UsState {
|
|
|
</span><span class="boring"> Alabama,
|
|
|
</span><span class="boring"> Alaska,
|
|
|
</span><span class="boring"> // --snip--
|
|
|
</span><span class="boring">}
|
|
|
</span><span class="boring">
|
|
|
</span><span class="boring">enum Coin {
|
|
|
</span><span class="boring"> Penny,
|
|
|
</span><span class="boring"> Nickel,
|
|
|
</span><span class="boring"> Dime,
|
|
|
</span><span class="boring"> Quarter(UsState),
|
|
|
</span><span class="boring">}
|
|
|
</span><span class="boring">
|
|
|
</span>fn value_in_cents(coin: Coin) -> u8 {
|
|
|
match coin {
|
|
|
Coin::Penny => 1,
|
|
|
Coin::Nickel => 5,
|
|
|
Coin::Dime => 10,
|
|
|
Coin::Quarter(state) => {
|
|
|
println!("State quarter from {state:?}!");
|
|
|
25
|
|
|
}
|
|
|
}
|
|
|
}
|
|
|
<span class="boring">
|
|
|
</span><span class="boring">fn main() {
|
|
|
</span><span class="boring"> value_in_cents(Coin::Quarter(UsState::Alaska));
|
|
|
</span><span class="boring">}</span></code></pre>
|
|
|
<p>如果调用 <code>value_in_cents(Coin::Quarter(UsState::Alaska))</code>,<code>coin</code> 将是 <code>Coin::Quarter(UsState::Alaska)</code>。当将值与每个分支相比较时,没有分支会匹配,直到遇到 <code>Coin::Quarter(state)</code>。这时,<code>state</code> 绑定的将会是值 <code>UsState::Alaska</code>。接着就可以在 <code>println!</code> 表达式中使用这个绑定了,像这样就可以获取 <code>Coin</code> 枚举的 <code>Quarter</code> 变体中内部的州的值。</p>
|
|
|
<h3 id="匹配-optiont"><a class="header" href="#匹配-optiont">匹配 <code>Option<T></code></a></h3>
|
|
|
<p>我们在之前的部分中使用 <code>Option<T></code> 时,是为了从 <code>Some</code> 中取出其内部的 <code>T</code> 值;我们还可以像处理 <code>Coin</code> 枚举那样使用 <code>match</code> 处理 <code>Option<T></code>!只不过这回比较的不再是硬币,而是 <code>Option<T></code> 的变体,但 <code>match</code> 表达式的工作方式保持不变。</p>
|
|
|
<p>比如我们想要编写一个函数,它获取一个 <code>Option<i32></code> ,如果其中含有一个值,将其加一。如果其中没有值,函数应该返回 <code>None</code> 值,而不尝试执行任何操作。</p>
|
|
|
<p>得益于 <code>match</code>,编写这个函数非常简单,它将看起来像示例 6-5 中这样:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2024"><span class="boring">fn main() {
|
|
|
</span> fn plus_one(x: Option<i32>) -> Option<i32> {
|
|
|
match x {
|
|
|
None => None,
|
|
|
Some(i) => Some(i + 1),
|
|
|
}
|
|
|
}
|
|
|
|
|
|
let five = Some(5);
|
|
|
let six = plus_one(five);
|
|
|
let none = plus_one(None);
|
|
|
<span class="boring">}</span></code></pre>
|
|
|
<p><span class="caption">示例 6-5:一个在 <code>Option<i32></code> 上使用 <code>match</code> 表达式的函数</span></p>
|
|
|
<p>让我们更仔细地检查 <code>plus_one</code> 的第一行操作。当调用 <code>plus_one(five)</code> 时,<code>plus_one</code> 函数体中的 <code>x</code> 将会是值 <code>Some(5)</code>。接着将其与每个分支比较。</p>
|
|
|
<pre><code class="language-rust ignore"><span class="boring">fn main() {
|
|
|
</span><span class="boring"> fn plus_one(x: Option<i32>) -> Option<i32> {
|
|
|
</span><span class="boring"> match x {
|
|
|
</span> None => None,
|
|
|
<span class="boring"> Some(i) => Some(i + 1),
|
|
|
</span><span class="boring"> }
|
|
|
</span><span class="boring"> }
|
|
|
</span><span class="boring">
|
|
|
</span><span class="boring"> let five = Some(5);
|
|
|
</span><span class="boring"> let six = plus_one(five);
|
|
|
</span><span class="boring"> let none = plus_one(None);
|
|
|
</span><span class="boring">}</span></code></pre>
|
|
|
<p>值 <code>Some(5)</code> 并不匹配模式 <code>None</code>,所以继续进行下一个分支。</p>
|
|
|
<pre><code class="language-rust ignore"><span class="boring">fn main() {
|
|
|
</span><span class="boring"> fn plus_one(x: Option<i32>) -> Option<i32> {
|
|
|
</span><span class="boring"> match x {
|
|
|
</span><span class="boring"> None => None,
|
|
|
</span> Some(i) => Some(i + 1),
|
|
|
<span class="boring"> }
|
|
|
</span><span class="boring"> }
|
|
|
</span><span class="boring">
|
|
|
</span><span class="boring"> let five = Some(5);
|
|
|
</span><span class="boring"> let six = plus_one(five);
|
|
|
</span><span class="boring"> let none = plus_one(None);
|
|
|
</span><span class="boring">}</span></code></pre>
|
|
|
<p><code>Some(5)</code> 与 <code>Some(i)</code> 匹配吗?当然匹配!它们是相同的变体。<code>i</code> 绑定了 <code>Some</code> 中包含的值,所以 <code>i</code> 的值是 <code>5</code>。接着匹配分支的代码被执行,所以我们将 <code>i</code> 的值加一并返回一个含有值 <code>6</code> 的新 <code>Some</code>。</p>
|
|
|
<p>接着考虑下示例 6-5 中 <code>plus_one</code> 的第二个调用,这里 <code>x</code> 是 <code>None</code>。我们进入 <code>match</code> 并与第一个分支相比较。</p>
|
|
|
<pre><code class="language-rust ignore"><span class="boring">fn main() {
|
|
|
</span><span class="boring"> fn plus_one(x: Option<i32>) -> Option<i32> {
|
|
|
</span><span class="boring"> match x {
|
|
|
</span> None => None,
|
|
|
<span class="boring"> Some(i) => Some(i + 1),
|
|
|
</span><span class="boring"> }
|
|
|
</span><span class="boring"> }
|
|
|
</span><span class="boring">
|
|
|
</span><span class="boring"> let five = Some(5);
|
|
|
</span><span class="boring"> let six = plus_one(five);
|
|
|
</span><span class="boring"> let none = plus_one(None);
|
|
|
</span><span class="boring">}</span></code></pre>
|
|
|
<p>匹配成功!这里没有值来加一,所以程序结束并返回 <code>=></code> 右侧的值 <code>None</code>,因为第一个分支就匹配到了,其他的分支将不再比较。</p>
|
|
|
<p>将 <code>match</code> 与枚举相结合在很多场景中都是有用的。你会在 Rust 代码中看到很多这样的模式:<code>match</code> 一个枚举,绑定其中的值到一个变量,接着根据其值执行代码。这在一开始有点复杂,不过一旦习惯了,你会希望所有语言都拥有它!这一直是用户的最爱。</p>
|
|
|
<h3 id="匹配是穷尽的"><a class="header" href="#匹配是穷尽的">匹配是穷尽的</a></h3>
|
|
|
<p><code>match</code> 还有另一方面需要讨论:这些分支必须覆盖了所有的可能性。考虑一下 <code>plus_one</code> 函数的这个版本,它有一个 bug 并不能编译:</p>
|
|
|
<pre><code class="language-rust ignore does_not_compile"><span class="boring">fn main() {
|
|
|
</span> fn plus_one(x: Option<i32>) -> Option<i32> {
|
|
|
match x {
|
|
|
Some(i) => Some(i + 1),
|
|
|
}
|
|
|
}
|
|
|
<span class="boring">
|
|
|
</span><span class="boring"> let five = Some(5);
|
|
|
</span><span class="boring"> let six = plus_one(five);
|
|
|
</span><span class="boring"> let none = plus_one(None);
|
|
|
</span><span class="boring">}</span></code></pre>
|
|
|
<p>我们没有处理 <code>None</code> 的情况,所以这些代码会造成一个 bug。幸运的是,这是一个 Rust 知道如何处理的 bug。如果尝试编译这段代码,会得到这个错误:</p>
|
|
|
<pre><code class="language-console">$ cargo run
|
|
|
Compiling enums v0.1.0 (file:///projects/enums)
|
|
|
error[E0004]: non-exhaustive patterns: `None` not covered
|
|
|
--> src/main.rs:3:15
|
|
|
|
|
|
|
3 | match x {
|
|
|
| ^ pattern `None` not covered
|
|
|
|
|
|
|
note: `Option<i32>` defined here
|
|
|
--> /rustc/4eb161250e340c8f48f66e2b929ef4a5bed7c181/library/core/src/option.rs:572:1
|
|
|
::: /rustc/4eb161250e340c8f48f66e2b929ef4a5bed7c181/library/core/src/option.rs:576:5
|
|
|
|
|
|
|
= note: not covered
|
|
|
= note: the matched value is of type `Option<i32>`
|
|
|
help: ensure that all possible cases are being handled by adding a match arm with a wildcard pattern or an explicit pattern as shown
|
|
|
|
|
|
|
4 ~ Some(i) => Some(i + 1),
|
|
|
5 ~ None => todo!(),
|
|
|
|
|
|
|
|
|
|
For more information about this error, try `rustc --explain E0004`.
|
|
|
error: could not compile `enums` (bin "enums") due to 1 previous error
|
|
|
</code></pre>
|
|
|
<p>Rust 知道我们没有覆盖所有可能的情况甚至知道哪些模式被忘记了!Rust 中的匹配是 <strong>穷尽的</strong>(<em>exhaustive</em>):必须穷举到最后的可能性来使代码有效。特别的在这个 <code>Option<T></code> 的例子中,Rust 防止我们忘记明确的处理 <code>None</code> 的情况,这让我们免于假设拥有一个实际上为空的值,从而使之前提到的价值亿万的错误不可能发生。</p>
|
|
|
<h3 id="通配模式和-_-占位符"><a class="header" href="#通配模式和-_-占位符">通配模式和 <code>_</code> 占位符</a></h3>
|
|
|
<p>使用枚举,我们也可以针对少数几个特定值执行特殊操作,而对其他所有值采取默认操作。想象我们正在玩一个游戏,如果你掷出骰子的值为 3,角色不会移动,而是会得到一顶新奇的帽子。如果你掷出了 7,你的角色将失去一顶新奇的帽子。对于其他的数值,你的角色会在棋盘上移动相应的格子。这是一个实现了上述逻辑的 <code>match</code>,骰子的结果是硬编码而不是一个随机值,其他的逻辑部分使用了没有函数体的函数来表示,实现它们超出了本例的范围:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2024"><span class="boring">fn main() {
|
|
|
</span> let dice_roll = 9;
|
|
|
match dice_roll {
|
|
|
3 => add_fancy_hat(),
|
|
|
7 => remove_fancy_hat(),
|
|
|
other => move_player(other),
|
|
|
}
|
|
|
|
|
|
fn add_fancy_hat() {}
|
|
|
fn remove_fancy_hat() {}
|
|
|
fn move_player(num_spaces: u8) {}
|
|
|
<span class="boring">}</span></code></pre>
|
|
|
<p>对于前两个分支,匹配模式是字面值 <code>3</code> 和 <code>7</code>,最后一个分支则涵盖了所有其他可能的值,模式是我们命名为 <code>other</code> 的一个变量。<code>other</code> 分支的代码通过将其传递给 <code>move_player</code> 函数来使用这个变量。</p>
|
|
|
<p>即使我们没有列出 <code>u8</code> 所有可能的值,这段代码依然能够编译,因为最后一个模式将匹配所有未被特殊列出的值。这种通配模式满足了 <code>match</code> 必须被穷尽的要求。请注意,我们必须将通配分支放在最后,因为模式是按顺序匹配的。如果我们在通配分支后添加其他分支,Rust 将会警告我们,因为此后的分支永远不会被匹配到。</p>
|
|
|
<p>Rust 还提供了一个模式,当我们不想使用通配模式获取的值时,请使用 <code>_</code> ,这是一个特殊的模式,可以匹配任意值而不绑定到该值。这告诉 Rust 我们不会使用这个值,所以 Rust 也不会警告我们存在未使用的变量。</p>
|
|
|
<p>让我们改变游戏规则:现在,当你掷出的值不是 3 或 7 的时候,你必须再次掷出。这种情况下我们不需要使用这个值,所以我们改动代码使用 <code>_</code> 来替代变量 <code>other</code> :</p>
|
|
|
<pre class="playground"><code class="language-rust edition2024"><span class="boring">fn main() {
|
|
|
</span> let dice_roll = 9;
|
|
|
match dice_roll {
|
|
|
3 => add_fancy_hat(),
|
|
|
7 => remove_fancy_hat(),
|
|
|
_ => reroll(),
|
|
|
}
|
|
|
|
|
|
fn add_fancy_hat() {}
|
|
|
fn remove_fancy_hat() {}
|
|
|
fn reroll() {}
|
|
|
<span class="boring">}</span></code></pre>
|
|
|
<p>这个例子也满足穷尽性要求,因为我们在最后一个分支中显式地忽略了其它值。我们没有忘记处理任何东西。</p>
|
|
|
<p>最后,让我们再次改变游戏规则,如果你掷出 3 或 7 以外的值,你的回合将无事发生。我们可以使用单元值(在<a href="ch03-02-data-types.html#元组类型">“元组类型”</a><!-- ignore -->一节中提到的空元组)作为 <code>_</code> 分支的代码:</p>
|
|
|
<pre class="playground"><code class="language-rust edition2024"><span class="boring">fn main() {
|
|
|
</span> let dice_roll = 9;
|
|
|
match dice_roll {
|
|
|
3 => add_fancy_hat(),
|
|
|
7 => remove_fancy_hat(),
|
|
|
_ => (),
|
|
|
}
|
|
|
|
|
|
fn add_fancy_hat() {}
|
|
|
fn remove_fancy_hat() {}
|
|
|
<span class="boring">}</span></code></pre>
|
|
|
<p>在这里,我们明确告诉 Rust 我们不会使用与前面模式不匹配的值,并且这种情况下我们不想运行任何代码。</p>
|
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<p>我们将在<a href="ch19-00-patterns.html">第十九章</a><!-- ignore -->中介绍更多关于模式和匹配的内容。现在,让我们继续讨论 <code>if let</code> 语法,这在 <code>match</code> 表达式显得有些冗长时非常有用。</p>
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