Upgrade to edition 2018

pull/280/head
Yuki Okushi 3 years ago
parent f30bc440db
commit 35f420981b
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@ -5,3 +5,6 @@ description = "The Dark Arts of Advanced and Unsafe Rust Programming"
[output.html] [output.html]
git-repository-url = "https://github.com/rust-lang/nomicon" git-repository-url = "https://github.com/rust-lang/nomicon"
[rust]
edition = "2018"

@ -2,7 +2,7 @@
Given the following code: Given the following code:
```rust,edition2018,compile_fail ```rust,compile_fail
#[derive(Debug)] #[derive(Debug)]
struct Foo; struct Foo;
@ -76,7 +76,7 @@ The following code fails to compile, because Rust doesn't understand that the bo
is no longer needed and conservatively falls back to using a whole scope for it. is no longer needed and conservatively falls back to using a whole scope for it.
This will eventually get fixed. This will eventually get fixed.
```rust,edition2018,compile_fail ```rust,compile_fail
# use std::collections::HashMap; # use std::collections::HashMap;
# use std::hash::Hash; # use std::hash::Hash;
fn get_default<'m, K, V>(map: &'m mut HashMap<K, V>, key: K) -> &'m mut V fn get_default<'m, K, V>(map: &'m mut HashMap<K, V>, key: K) -> &'m mut V

@ -226,7 +226,7 @@ The following snippet compiles, because after printing `x`, it is no longer
needed, so it doesn't matter if it is dangling or aliased (even though the needed, so it doesn't matter if it is dangling or aliased (even though the
variable `x` *technically* exists to the very end of the scope). variable `x` *technically* exists to the very end of the scope).
```rust,edition2018 ```rust
let mut data = vec![1, 2, 3]; let mut data = vec![1, 2, 3];
let x = &data[0]; let x = &data[0];
println!("{}", x); println!("{}", x);
@ -238,7 +238,7 @@ However, if the value has a destructor, the destructor is run at the end of the
scope. And running the destructor is considered a use obviously the last one. scope. And running the destructor is considered a use obviously the last one.
So, this will *not* compile. So, this will *not* compile.
```rust,edition2018,compile_fail ```rust,compile_fail
#[derive(Debug)] #[derive(Debug)]
struct X<'a>(&'a i32); struct X<'a>(&'a i32);
@ -258,7 +258,7 @@ One way to convince the compiler that `x` is no longer valid is by using `drop(x
Furthermore, there might be multiple possible last uses of the borrow, for Furthermore, there might be multiple possible last uses of the borrow, for
example in each branch of a condition. example in each branch of a condition.
```rust,edition2018 ```rust
# fn some_condition() -> bool { true } # fn some_condition() -> bool { true }
let mut data = vec![1, 2, 3]; let mut data = vec![1, 2, 3];
let x = &data[0]; let x = &data[0];
@ -278,7 +278,7 @@ borrows just being tied to the same local variable. This often happens around
loops (writing a new value of a variable at the end of the loop and using it for loops (writing a new value of a variable at the end of the loop and using it for
the last time at the top of the next iteration). the last time at the top of the next iteration).
```rust,edition2018 ```rust
let mut data = vec![1, 2, 3]; let mut data = vec![1, 2, 3];
// This mut allows us to change where the reference points to // This mut allows us to change where the reference points to
let mut x = &data[0]; let mut x = &data[0];

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