Merge pull request #82 from RalfJung/ffi

Don’t recommend empty enums for opaque types
pull/84/head
Steve Klabnik 6 years ago committed by GitHub
commit 4b3335d0da
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@ -737,11 +737,11 @@ void foo(struct Foo *arg);
void bar(struct Bar *arg); void bar(struct Bar *arg);
``` ```
To do this in Rust, lets create our own opaque types with `enum`: To do this in Rust, lets create our own opaque types:
```rust ```rust
pub enum Foo {} #[repr(C)] pub struct Foo { _private: [u8; 0] }
pub enum Bar {} #[repr(C)] pub struct Bar { _private: [u8; 0] }
extern "C" { extern "C" {
pub fn foo(arg: *mut Foo); pub fn foo(arg: *mut Foo);
@ -750,7 +750,18 @@ extern "C" {
# fn main() {} # fn main() {}
``` ```
By using an `enum` with no variants, we create an opaque type that we cant By including a private field and no constructor,
instantiate, as it has no variants. But because our `Foo` and `Bar` types are we create an opaque type that we can't instantiate outside of this module.
(A struct with no field could be instantiated by anyone.)
We also want to use this type in FFI, so we have to add `#[repr(C)]`.
And to avoid warning around using `()` in FFI, we instead use an empty array,
which works just as well as an empty type but is FFI-compatible.
But because our `Foo` and `Bar` types are
different, well get type safety between the two of them, so we cannot different, well get type safety between the two of them, so we cannot
accidentally pass a pointer to `Foo` to `bar()`. accidentally pass a pointer to `Foo` to `bar()`.
Notice that it is a really bad idea to use an empty enum as FFI type.
The compiler relies on empty enums being uninhabited, so handling values of type
`&Empty` is a huge footgun and can lead to buggy program behavior (by triggering
undefined behavior).

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