rust
/
nomicon
mirror of https://github.com/rust-lang/nomicon
1
0
Fork 0
Code Issues Packages Projects Releases Wiki Activity

Subtyping rewrite

Browse Source
pull/102/head
Alexis Beingessner 7 years ago
parent 7a5aa3ab3a
commit b28d364f0f
1 changed files with 334 additions and 169 deletions
Show Stats Download Patch File Download Diff File

503
src/subtyping.md
Unescape View File

@ -3,53 +3,133 @@
Subtyping is a relationship between types that allows statically typed Subtyping is a relationship between types that allows statically typed
languages to be a bit more flexible and permissive. languages to be a bit more flexible and permissive.
The most common and easy to understand example of this can be found in Subtyping in Rust is a bit different from subtyping in other languages. This leads
languages with inheritance. Consider an Animal type which has an `eat()` to examples of subtyping being *a bit* convoluted. This is especially unforunate
method, and a Cat type which extends Animal, adding a `meow()` method. because subtyping, and especially variance, are actually really hard to
Without subtyping, if someone were to write a `feed(Animal)` function, they understand properly. As in, even compiler writers mess it up all the time.
wouldn't be able to pass a Cat to this function, because a Cat isn't *exactly*
an Animal. But being able to pass a Cat where an Animal is expected seems In order to make examples that are simple and concise, this section will consider a
fairly reasonable. After all, a Cat is just an Animal *and more*. Something *small* extension to the Rust language to introduce subtyping in a way that is more
having extra features that can be ignored shouldn't be any impediment to similar to other languages. After establishing concepts and issues under this simpler
using it! system, we will then relate it back to how subtyping actually occurs in Rust.
This is exactly what subtyping lets us do. Because a Cat is an Animal *and more* So here's our simple extension, *Objective Rust*, featuring three new types:
we say that Cat is a *subtype* of Animal. We then say that anywhere a value of
a certain type is expected, a value with a subtype can also be supplied. Ok
actually it's a lot more complicated and subtle than that, but that's the ```rust
basic intuition that gets you by in 99% of the cases. We'll cover why it's trait Animal {
*only* 99% later in this section. fn snuggle(&self);
fn eat(&mut self);
Although Rust doesn't have any notion of structural inheritance, it *does* }
include subtyping. In Rust, subtyping derives entirely from lifetimes. Since
lifetimes are regions of code, we can partially order them based on the trait Cat: Animal {
*contains* (outlives) relationship. fn meow(&self);
}
Subtyping on lifetimes is in terms of that relationship: if `'big: 'small`
("big contains small" or "big outlives small"), then `'big` is a subtype trait Dog: Animal {
fn bark(&self);
}
```
But unlike normal traits, we can use them as concrete and sized types, just like structs.
Now, say we have a very simple function that takes an Animal, like this:
```rust,ignore
fn love(pet: Animal) {
pet.snuggle();
}
```
By default, static types must match *exactly* for a program to compile. As such,
this code won't compile:
```rust,ignore
let mr_snuggles: Cat = ...;
love(mr_snuggles); // ERROR: expected Animal, found Cat
```
Mr. Snuggles is a Cat, and Cats aren't *exactly* Animals, so we can't love him! 😿
This is especially annoying because Cats *are* Animals. They support every operation
an Animal supports, so intuitively `love` shouldn't care if we pass it a `Cat`.
Or, to put it another way, we should be able to just *forget* the non-animal
parts of our `Cat`, as they aren't necessary to love it.
This is exactly the problem that *subtyping* is intended to fix. Because Cats are just
Animals *and more*, we say Cat is a *subtype* of Animal (because Cats are a *subset*
of all the Animals). Equivalently, we can say that Animal is a *supertype* of Cat.
With subtypes, we can tweak our overly strict static type system
with a simple rule: anywhere a value of some type `T` is expected, we *also* accept
values that are *subtypes* of `T`.
Or more concretely: anywhere an Animal is expected, a Cat or Dog will also work.
As we will see throughout the rest of this section, subtyping is a lot more complicated
and subtle than this, but this simple rule is a very good 99% intuition. And unless you
write unsafe code, the compiler will automatically handle all the corner cases for you.
But this is the Rustonomicon. We're writing unsafe code, so we need to understand how
this stuff really works, and how we can mess it up.
The core problem is that this rule, naively applied, will lead to *Meowing Dogs*. That is,
we can convince someone that a Dog is actually a Cat. This completely destroys the fabric
of our static type system, making it worse than useless (and leading to Undefined Behaviour).
Here's a simple example of this happening when we apply subtyping in a completely naive
"find and replace" way.
```rust,ignore
fn evil_feeder(pet: &mut Animal) {
let spike: Dog = ...;
// `pet` is an Animal, and Dog is a subtype of Animal,
// so this should be fine, right..?
*pet = spike;
}
fn main() {
let mut mr_snuggles: Cat = ...;
evil_feeder(&mut mr_snuggles); // Replaces mr_snuggles with a Dog
mr_snuggles.meow(); // OH NO, MEOWING DOG!
}
```
Clearly, we need a more robust system than "find and replace". That system is *variance*,
the rules governing how subtyping *composes*.
But before we get into variance, let's take a quick peek at where subtyping actually occurs in
Rust: *lifetimes*!
> NOTE: The typed-ness of lifetimes is a fairly arbitrary construct that some
> disagree with. However it simplifies our analysis to treat lifetimes
> and types uniformly.
Lifetimes are just regions of code, and regions can be partially ordered with the *contains*
(outlives) relationship. Subtyping on lifetimes is in terms of that relationship:
if `'big: 'small` ("big contains small" or "big outlives small"), then `'big` is a subtype
of `'small`. This is a large source of confusion, because it seems backwards of `'small`. This is a large source of confusion, because it seems backwards
to many: the bigger region is a *subtype* of the smaller region. But it makes to many: the bigger region is a *subtype* of the smaller region. But it makes
sense if you consider our Animal example: *Cat* is an Animal *and more*, sense if you consider our Animal example: Cat is an Animal *and more*,
just as `'big` is `'small` *and more*. just as `'big` is `'small` *and more*.
Put another way, if someone wants a reference that lives for `'small`, Put another way, if someone wants a reference that lives for `'small`,
usually what they actually mean is that they want a reference that lives usually what they actually mean is that they want a reference that lives
for *at least* `'small`. They don't actually care if the lifetimes match for *at least* `'small`. They don't actually care if the lifetimes match
exactly. For this reason `'static`, the forever lifetime, is a subtype exactly. So it should be ok for us to *forget* that we live for `'big`.
of every lifetime.
Higher-ranked lifetimes are also subtypes of every concrete lifetime. This is
because taking an arbitrary lifetime is strictly more general than taking a
specific one.
(The typed-ness of lifetimes is a fairly arbitrary construct that some The meowing dog problem for lifetimes will result in us being able to
disagree with. However it simplifies our analysis to treat lifetimes store a short-lived reference in a place that expects a longer-lived one,
and types uniformly.) creating a dangling reference and letting us use-after-free.
However you can't write a function that takes a value of type `'a`! Lifetimes It will be useful to note that `'static`, the forever lifetime, is a subtype of
are always just part of another type, so we need a way of handling that. every lifetime because by definition it outlives everything. We will be using
To handle it, we need to talk about *variance*. this relationship frequently in examples.
With all that said, we still have no idea how to actually *use* subtyping of lifetimes,
because nothing ever has type `'a`. Lifetimes only occur as part of some larger type
like `&'a u32` or `IterMut<'a, u32>`. To apply lifetime subtyping, we need to know
how to *compose* subtyping. Once again, we need *variance*.
@ -59,200 +139,284 @@ To handle it, we need to talk about *variance*.
Variance is where things get a bit complicated. Variance is where things get a bit complicated.
Variance is a property that *type constructors* have with respect to their Variance is a property that *type constructors* have with respect to their
arguments. A type constructor in Rust is a generic type with unbound arguments. arguments. A type constructor in Rust is any generic type with unbound arguments.
For instance `Vec` is a type constructor that takes a `T` and returns a For instance `Vec` is a type constructor that takes a type `X` and returns
`Vec<T>`. `&` and `&mut` are type constructors that take two inputs: a `Vec<X>`. `&` and `&mut` are type constructors that take two inputs: a
lifetime, and a type to point to. lifetime, and a type to point to.
> NOTE: For convenience we will often refer to `F<T>` as a type constructor just so
> that we can easily talk about `T`. Hopefully this is clear in context.
A type constructor F's *variance* is how the subtyping of its inputs affects the A type constructor F's *variance* is how the subtyping of its inputs affects the
subtyping of its outputs. There are three kinds of variance in Rust: subtyping of its outputs. There are three kinds of variance in Rust. Given two
types `Sub` and `Super`, where `Sub` is a subtype of `Super`:
* `F` is *covariant* if `F<Sub>` is a subtype of `F<Super>` (subtyping "passes through")
* `F` is *contravariant* if `F<Super>` is a subtype of `F<Sub>` (subtyping is "inverted")
* `F` is *invariant* otherwise (no subtyping relationship exists)
If `F` has multiple type parameters, we can talk about the individual variances
by saying that, for example, `F<T, U>` is covariant over `T` and invariant over `U`.
It is *very useful* to keep in mind that covariance is, in practical terms, "the"
variance. Almost all consideration of variance is in terms of whether something
should be covariant or invariant. Actually witnessing contravariance is quite difficult
in Rust, though it does in fact exist.
Here is a table of important variances which the rest of this section will be devoted
to trying to explain:
| | | 'a | T | U |
|---|---------------|:---------:|:-----------------:|:---------:|
| * | &'a T | covariant | covariant | |
| * | &'a mut T | covariant | invariant | |
| * | Box<T> | | covariant | |
| | Vec<T> | | covariant | |
| * | UnsafeCell<T> | | invariant | |
| | Cell<T> | | invariant | |
| * | fn(T) -> U | | **contra**variant | covariant |
| | *const T | | covariant | |
| | *mut T | | invariant | |
These types with \*'s are the ones we will be focusing on, as they are in
some sense "fundamental". All the others can be understood by analogy to the others:
* Vec and all other owning pointers and collections follow the same logic as Box
* Cell and all other interior mutability types follow the same logic as UnsafeCell
* `*const` follows the logic of `&T`
* `*mut` follows the logic of `&mut T` (or `UnsafeCell<T>`)
> NOTE: the *only* source of contravariance in the language is the arguments to
> a function, which is why it really doesn't come up much in practice. Invoking
> contravariance involves higher-order programming with function pointers that
> take references with specific lifetimes (as opposed to the usual "any lifetime",
> which gets into higher rank lifetimes which work independently of subtyping).
Ok, that's enough type theory! Let's try to apply the concept of variance to Rust,
and look at some examples.
First off, let's revisit the meowing dog example:
```rust,ignore
fn evil_feeder(pet: &mut Animal) {
let spike: Dog = ...;
// `pet` is an Animal, and Dog is a subtype of Animal,
// so this should be fine, right..?
*pet = spike;
}
* F is *covariant* over `T` if `T` being a subtype of `U` implies fn main() {
`F<T>` is a subtype of `F<U>` (subtyping "passes through") let mut mr_snuggles: Cat = ...;
* F is *contravariant* over `T` if `T` being a subtype of `U` implies evil_feeder(&mut mr_snuggles); // Replaces mr_snuggles with a Dog
`F<U>` is a subtype of `F<T>` (subtyping is "inverted") mr_snuggles.meow(); // OH NO, MEOWING DOG!
* F is *invariant* over `T` otherwise (no subtyping relation can be derived) }
```
It should be noted that covariance is *far* more common and important than If we look at our table of variances, we see that `&mut T` is *invariant* over `T`.
contravariance in Rust. The existence of contravariance in Rust can mostly As it turns out, this completely fixes the issue! With invariance, the fact that
be ignored. Cat is a subtype of Animal doesn't matter; `&mut Cat` still won't be a subtype of
`&mut Animal`. The static type checker will then correctly stop us from passing
a Cat into `evil_feeder`.
Some important variances (which we will explain in detail below): The soundness of subtyping is based on the idea that it's ok to forget unnecessary
details. But with references, there's always someone that remembers those details:
the value being referenced. That value expects those details to keep being true,
and may behave incorrectly if its expectations are violated.
* `&'a T` is covariant over `'a` and `T` (as is `*const T` by metaphor) The problem with making `&mut T` covariant over `T` is that it gives us the power
* `&'a mut T` is covariant over `'a` but invariant over `T` to modify the original value *when we don't remember all of its constraints*.
* `fn(T) -> U` is **contra**variant over `T`, but covariant over `U` And so, we can make someone have a Dog when they're certain they still have a Cat.
* `Box`, `Vec`, and all other collections are covariant over the types of
their contents
* `UnsafeCell<T>`, `Cell<T>`, `RefCell<T>`, `Mutex<T>` and all other
interior mutability types are invariant over T (as is `*mut T` by metaphor)
To understand why these variances are correct and desirable, we will consider With that established, we can easily see why `&T` being covariant over `T` *is*
several examples. sound: it doesn't let you modify the value, only look at it. Without anyway to
mutate, there's no way for us to mess with any details. We can also see why
UnsafeCell and all the other interior mutability types must be invariant: they
make `&T` work like `&mut T`!
We have already covered why `&'a T` should be covariant over `'a` when Now what about the lifetime on references? Why is it ok for both kinds of references
introducing subtyping: it's desirable to be able to pass longer-lived things to be covariant over their lifetimes. Well, here's a two-pronged argument:
where shorter-lived things are needed.
Similar reasoning applies to why it should be covariant over T: it's reasonable First and foremost, subtyping references based on their lifetimes is *the entire point
to be able to pass `&&'static str` where an `&&'a str` is expected. The of subtyping in Rust*. The only reason we have subtyping is so we can pass
additional level of indirection doesn't change the desire to be able to pass long-lived things where short-lived things are expected. So it better work!
longer lived things where shorter lived things are expected.
However this logic doesn't apply to `&mut`. To see why `&mut` should Second, and more seriously, references *own* their lifetimes, while they are
be invariant over T, consider the following code: only borrowing their referents. If you shrink down a reference's lifetime when
you hand it to someone, that location now has a reference which owns the smaller
lifetime. There's no way to mess with original reference's lifetime using the
other one.
Or rather, the only way to mess with someone's lifetime is to build a meowing dog,
and as soon as you try to build a meowing dog the lifetime should be wrapped up
in an invariant context, preventing the lifetime from being shrunk. That's probably
a little too abstract, so let's port the meowing dog problem over to real Rust.
In the meowing dog problem we take a subtype (Cat), convert it into a supertype
(Animal), and then use that fact to overwrite the subtype with a value that satisfies
the constraints of the supertype but not the subtype (Dog).
So with lifetimes, we want to take a long-lived thing, convert it into a
short-lived thing, and then use that to write something that doesn't live long
enough into the place expecting something long-lived.
Here it is:
```rust,ignore ```rust,ignore
fn overwrite<T: Copy>(input: &mut T, new: &mut T) { fn evil_feeder<T>(input: &mut T, val: T) {
*input = *new; *input = val;
} }
fn main() { fn main() {
let mut forever_str: &'static str = "hello"; let mut mr_snuggles: &'static str = "meow! :3"; // mr. snuggles forever!!
{ {
let string = String::from("world"); let spike = String::from("bark! >:V");
overwrite(&mut forever_str, &mut &*string); let spike_str: &str = &spike; // Only lives for the block
evil_feeder(&mut mr_snuggles, spike_str); // EVIL!
} }
// Oops, printing free'd memory println!("{}", mr_snuggles); // Use after free?
println!("{}", forever_str);
} }
``` ```
The signature of `overwrite` is clearly valid: it takes mutable references to And what do we get when we run this?
two values of the same type, and overwrites one with the other.
```text
But, if `&mut T` was covariant over T, then `&mut &'static str` would be a error[E0597]: `spike` does not live long enough
subtype of `&mut &'a str`, since `&'static str` is a subtype of `&'a str`. --> src/main.rs:9:32
Therefore the lifetime of `forever_str` would successfully be "shrunk" down |
to the shorter lifetime of `string`, and `overwrite` would be called successfully. 9 | let spike_str: &str = &spike;
`string` would subsequently be dropped, and `forever_str` would point to | ^^^^^ borrowed value does not live long enough
freed memory when we print it! Therefore `&mut` should be invariant. 10 | evil_feeder(&mut mr_snuggles, spike_str);
11 | }
This is the general theme of variance vs invariance: if variance would allow you | - borrowed value only lives until here
to store a short-lived value in a longer-lived slot, then invariance must be used. |
= note: borrowed value must be valid for the static lifetime...
More generally, the soundness of subtyping and variance is based on the idea that its ok to ```
forget details, but with mutable references there's always someone (the original
value being referenced) that remembers the forgotten details and will assume Good! It doesn't compile! Let's break down what's happening here in detail.
that those details haven't changed. If we do something to invalidate those details,
the original location can behave unsoundly. First let's look at the new `evil_feeder` function:
However it *is* sound for `&'a mut T` to be covariant over `'a`. The key difference
between `'a` and T is that `'a` is a property of the reference itself,
while T is something the reference is borrowing. If you change T's type, then
the source still remembers the original type. However if you change the
lifetime's type, no one but the reference knows this information, so it's fine.
Put another way: `&'a mut T` owns `'a`, but only *borrows* T.
`Box` and `Vec` are interesting cases because they're covariant, but you can
definitely store values in them! This is where Rust's typesystem allows it to
be a bit more clever than others. To understand why it's sound for owning
containers to be covariant over their contents, we must consider
the two ways in which a mutation may occur: by-value or by-reference.
If mutation is by-value, then the old location that remembers extra details is
moved out of, meaning it can't use the value anymore. So we simply don't need to
worry about anyone remembering dangerous details. Put another way, applying
subtyping when passing by-value *destroys details forever*. For example, this
compiles and is fine:
```rust ```rust
fn get_box<'a>(str: &'a str) -> Box<&'a str> { fn evil_feeder<T>(input: &mut T, val: T) {
// String literals are `&'static str`s, but it's fine for us to *input = val;
// "forget" this and let the caller think the string won't live that long.
Box::new("hello")
} }
``` ```
If mutation is by-reference, then our container is passed as `&mut Vec<T>`. But All it does it take a mutable reference and a value and overwrite the referent with it.
`&mut` is invariant over its value, so `&mut Vec<T>` is actually invariant over `T`. What's important about this function is that it creates a type equality constraint. It
So the fact that `Vec<T>` is covariant over `T` doesn't matter at all when clearly says in its signature the referent and the value must be the *exact same* type.
mutating by-reference.
But being covariant still allows `Box` and `Vec` to be weakened when shared Meanwhile, in the caller we pass in `&mut &'static str` and `&'spike_str str`.
immutably. So you can pass a `&Vec<&'static str>` where a `&Vec<&'a str>` is
expected.
The invariance of the cell types can be seen as follows: `&` is like an `&mut` Because `&mut T` is invariant over `T`, the compiler concludes it can't apply any subtyping
for a cell, because you can still store values in them through an `&`. Therefore to the first argument, and so `T` must be exactly `&'static str`.
cells must be invariant to avoid lifetime smuggling.
`fn` is the most subtle case because they have mixed variance, and in fact are `&'a str` *is* covariant over `'a` so the compiler adopts a constraint: `&'spike_str str`
the only source of **contra**variance. To see why `fn(T) -> U` should be contravariant must be a subtype of `&'static str` (inclusive), which in turn implies `'spike_str`
over T, consider the following function signature: must be subtype `'static` (inclusive). Which is to say, `'spike_str` must contain
`'static`. But only one thing contains `'static` -- `'static` itself!
```rust,ignore This is why we get the error when we try to assign `&spike` to `spike_str`. The
// 'a is derived from some parent scope compiler has worked backwards to conclude `spike_str` must live forever, and `&spike`
fn foo(&'a str) -> usize; simply can't live that long.
```
So even though references are covariant over their lifetimes, they "inherit" invariance
whenever they're put into a context that could do something bad with that. In this case,
we inherited invariance as soon as we put our reference inside an `&mut T`.
As it turns out, the argument for why it's ok for Box (and Vec, Hashmap, etc.) to
be covariant is pretty similar to the argument for why it's ok for why it's ok for
lifetimes to be covariant: as soon as you try to stuff them in something like a
mutable reference, they inherit invariance and you're prevented from doing anything
bad!
However Box makes it easier to focus on the *owning* aspect of references that we
partially glossed over.
This signature claims that it can handle any `&str` that lives at least as Unlike a lot of languages which allow values to be freely aliased at all times,
long as `'a`. Now if this signature was **co**variant over `&'a str`, that Rust has a very strict rule: if you're allowed to mutate or move a value, you
would mean are guaranteed to be the only one with access to it.
Consider the following code:
```rust,ignore ```rust,ignore
fn foo(&'static str) -> usize; let mr_snuggles: Box<Cat> = ..;
let spike: Box<Dog> = ..;
let mut pet: Box<Animal>;
pet = mr_snuggles;
pet = spike;
``` ```
could be provided in its place, as it would be a subtype. However this function There is no problem at all with the fact that we have forgotten that `mr_snuggles` was a Cat,
has a stronger requirement: it says that it can only handle `&'static str`s, or that we overwrote him with a Dog, because as soon as we moved mr_snuggles to a variable
and nothing else. Giving `&'a str`s to it would be unsound, as it's free to that only knew he was an Animal, *we destroyed the only thing in the universe that
assume that what it's given lives forever. Therefore functions definitely shouldn't rememembered he was a Cat*!
be **co**variant over their arguments.
However if we flip it around and use **contra**variance, it *does* work! If In contrast to the argument about immutable references being soundly covariant because they
something expects a function which can handle strings that live forever, don't let you change anything, owned values can be covariant because they make you
it makes perfect sense to instead provide a function that can handle change *everything*. There is no connection between old locations and new locations.
strings that live for *less* than forever. So Applying by-value subtyping is an irreversible act of knowledge destruction, and
without any memory of how things used to be, no one can be tricked into acting on
that old information!
Only one thing left to explain: function pointers. To see why
`fn(T) -> U` should be covariant over `U`, consider the following signature:
```rust,ignore ```rust,ignore
fn foo(&'a str) -> usize; fn get_animal() -> Animal;
``` ```
can be passed where This function claims to produce an Animal. As such, it is perfectly valid to
provide a function with the following signature instead:
```rust,ignore ```rust,ignore
fn foo(&'static str) -> usize; fn get_animal() -> Cat;
``` ```
is expected. After all, Cats are Animals, so always producing a Cat is a perfectly valid way
to produce Animals. Or to relate it back to real Rust: if we need a function
that is supposed to produce something that lives for `'short`, it's perfectly
fine for it to produce something that lives for `'long`. We don't care, we can
just forget that fact.
To see why `fn(T) -> U` should be **co**variant over U, consider the following However, the same logic does not apply to *arguments*. Consider trying to satisfy:
function signature:
```rust,ignore ```rust,ignore
// 'a is derived from some parent scope fn handle_animal(Animal);
fn foo(usize) -> &'a str;
``` ```
This signature claims that it will return something that outlives `'a`. It is with
therefore completely reasonable to provide
```rust,ignore ```rust,ignore
fn foo(usize) -> &'static str; fn handle_animal(Cat);
``` ```
in its place, as it does indeed return things that outlive `'a`. Therefore The first function can accept Dogs, but the second function absolutely can't.
functions are covariant over their return type. Covariance doesn't work here. But if we flip it around, it actually *does*
work! If we need a function that can handle Cats, a function that can handle *any*
Animal will surely work fine. Or to relate it back to real Rust: if we need a
function that can handle anything that lives for at least `'long`, it's perfectly
fine for it to be able to handle anything that lives for at least `'short`.
`*const` has the exact same semantics as `&`, so variance follows. `*mut` on the And that's why function types, unlike anything else in the language, are
other hand can dereference to an `&mut` whether shared or not, so it is marked **contra**variant over their arguments.
as invariant just like cells.
This is all well and good for the types the standard library provides, but Now, this is all well and good for the types the standard library provides, but
how is variance determined for type that *you* define? A struct, informally how is variance determined for type that *you* define? A struct, informally
speaking, inherits the variance of its fields. If a struct `Foo` speaking, inherits the variance of its fields. If a struct `MyType`
has a generic argument `A` that is used in a field `a`, then Foo's variance has a generic argument `A` that is used in a field `a`, then MyType's variance
over `A` is exactly `a`'s variance. However if `A` is used in multiple fields: over `A` is exactly `a`'s variance. However if `A` is used in multiple fields:
* If all uses of A are covariant, then Foo is covariant over A * If all uses of `A` are covariant, then MyType is covariant over `A`
* If all uses of A are contravariant, then Foo is contravariant over A * If all uses of `A` are contravariant, then MyType is contravariant over `A`
* Otherwise, Foo is invariant over A * Otherwise, MyType is invariant over `A`
```rust ```rust
use std::cell::Cell; use std::cell::Cell;
struct Foo<'a, 'b, A: 'a, B: 'b, C, D, E, F, G, H, In, Out, Mixed> { struct MyType<'a, 'b, A: 'a, B: 'b, C, D, E, F, G, H, In, Out, Mixed> {
a: &'a A, // covariant over 'a and A a: &'a A, // covariant over 'a and A
b: &'b mut B, // covariant over 'b and invariant over B b: &'b mut B, // covariant over 'b and invariant over B
@ -272,3 +436,4 @@ struct Foo<'a, 'b, A: 'a, B: 'b, C, D, E, F, G, H, In, Out, Mixed> {
k2: Mixed, // invariant over Mixed, because invariance wins all conflicts k2: Mixed, // invariant over Mixed, because invariance wins all conflicts
} }
``` ```

Write Preview
Loading…
Cancel
Save