expand lifetime splitting to show IterMut is totally safe

pull/10/head
Alexis Beingessner 9 years ago committed by Manish Goregaokar
parent 1e43aaa054
commit f8fdc70bc3

@ -1,10 +1,10 @@
% Splitting Lifetimes
The mutual exclusion property of mutable references can be very limiting when
working with a composite structure. The borrow checker understands some basic stuff, but
will fall over pretty easily. It *does* understand structs sufficiently to
know that it's possible to borrow disjoint fields of a struct simultaneously.
So this works today:
working with a composite structure. The borrow checker understands some basic
stuff, but will fall over pretty easily. It *does* understand structs
sufficiently to know that it's possible to borrow disjoint fields of a struct
simultaneously. So this works today:
```rust
struct Foo {
@ -49,11 +49,11 @@ container types like a tree, especially if distinct keys actually *do* map
to the same value.
In order to "teach" borrowck that what we're doing is ok, we need to drop down
to unsafe code. For instance, mutable slices expose a `split_at_mut` function that
consumes the slice and returns *two* mutable slices. One for everything to the
left of the index, and one for everything to the right. Intuitively we know this
is safe because the slices don't alias. However the implementation requires some
unsafety:
to unsafe code. For instance, mutable slices expose a `split_at_mut` function
that consumes the slice and returns *two* mutable slices. One for everything to
the left of the index, and one for everything to the right. Intuitively we know
this is safe because the slices don't alias. However the implementation requires
some unsafety:
```rust,ignore
fn split_at_mut(&mut self, mid: usize) -> (&mut [T], &mut [T]) {
@ -66,9 +66,9 @@ fn split_at_mut(&mut self, mid: usize) -> (&mut [T], &mut [T]) {
}
```
This is pretty plainly dangerous. We use transmute to duplicate the slice with an
*unbounded* lifetime, so that it can be treated as disjoint from the other until
we unify them when we return.
This is pretty plainly dangerous. We use transmute to duplicate the slice with
an *unbounded* lifetime, so that it can be treated as disjoint from the other
until we unify them when we return.
However more subtle is how iterators that yield mutable references work.
The iterator trait is defined as follows:
@ -81,60 +81,201 @@ trait Iterator {
}
```
Given this definition, Self::Item has *no* connection to `self`. This means
that we can call `next` several times in a row, and hold onto all the results
*concurrently*. This is perfectly fine for by-value iterators, which have exactly
these semantics. It's also actually fine for shared references, as they admit
arbitrarily many references to the same thing (although the
iterator needs to be a separate object from the thing being shared). But mutable
references make this a mess. At first glance, they might seem completely
incompatible with this API, as it would produce multiple mutable references to
the same object!
Given this definition, Self::Item has *no* connection to `self`. This means that
we can call `next` several times in a row, and hold onto all the results
*concurrently*. This is perfectly fine for by-value iterators, which have
exactly these semantics. It's also actually fine for shared references, as they
admit arbitrarily many references to the same thing (although the iterator needs
to be a separate object from the thing being shared).
But mutable references make this a mess. At first glance, they might seem
completely incompatible with this API, as it would produce multiple mutable
references to the same object!
However it actually *does* work, exactly because iterators are one-shot objects.
Everything an IterMut yields will be yielded *at most* once, so we don't *actually*
ever yield multiple mutable references to the same piece of data.
Everything an IterMut yields will be yielded *at most* once, so we don't
*actually* ever yield multiple mutable references to the same piece of data.
In general all mutable iterators require *some* unsafe code *somewhere*, though.
Whether it's raw pointers, or safely composing on top of *another* IterMut.
Perhaps surprisingly, mutable iterators *don't* require unsafe code to be
implemented for many types!
For instance, VecDeque's IterMut:
For instance here's a singly linked list:
```rust,ignore
struct IterMut<'a, T:'a> {
// The whole backing array. Some of these indices are initialized!
ring: &'a mut [T],
tail: usize,
head: usize,
```rust
# fn main() {}
type Link<T> = Option<Box<Node<T>>>;
struct Node<T> {
elem: T,
next: Link<T>,
}
pub struct LinkedList<T> {
head: Link<T>,
}
pub struct IterMut<'a, T: 'a>(Option<&'a mut Node<T>>);
impl<T> LinkedList<T> {
fn iter_mut(&mut self) -> IterMut<T> {
IterMut(self.head.as_mut().map(|node| &mut **node))
}
}
impl<'a, T> Iterator for IterMut<'a, T> {
type Item = &'a mut T;
fn next(&mut self) -> Option<&'a mut T> {
if self.tail == self.head {
return None;
fn next(&mut self) -> Option<Self::Item> {
self.0.take().map(|node| {
self.0 = node.next.as_mut().map(|node| &mut **node);
&mut node.elem
})
}
let tail = self.tail;
self.tail = wrap_index(self.tail.wrapping_add(1), self.ring.len());
}
```
unsafe {
// might as well do unchecked indexing since wrap_index has us
// in-bounds, and many of the "middle" indices are uninitialized
// anyway.
let elem = self.ring.get_unchecked_mut(tail);
Here's a mutable slice:
```rust
use std::mem;
pub struct IterMut<'a, T: 'a>(&'a mut[T]);
impl<'a, T> Iterator for IterMut<'a, T> {
type Item = &'a mut T;
fn next(&mut self) -> Option<Self::Item> {
let slice = mem::replace(&mut self.0, &mut []);
if slice.is_empty() { return None; }
let (l, r) = slice.split_at_mut(1);
self.0 = r;
l.get_mut(0)
}
}
impl<'a, T> DoubleEndedIterator for IterMut<'a, T> {
fn next_back(&mut self) -> Option<Self::Item> {
let slice = mem::replace(&mut self.0, &mut []);
if slice.is_empty() { return None; }
let new_len = slice.len() - 1;
let (l, r) = slice.split_at_mut(new_len);
self.0 = l;
r.get_mut(0)
}
}
```
And here's a binary tree:
```rust
use std::collections::VecDeque;
type Link<T> = Option<Box<Node<T>>>;
struct Node<T> {
elem: T,
left: Link<T>,
right: Link<T>,
}
pub struct Tree<T> {
root: Link<T>,
}
struct NodeIterMut<'a, T: 'a> {
elem: Option<&'a mut T>,
left: Option<&'a mut Node<T>>,
right: Option<&'a mut Node<T>>,
}
enum State<'a, T: 'a> {
Elem(&'a mut T),
Node(&'a mut Node<T>),
}
pub struct IterMut<'a, T: 'a>(VecDeque<NodeIterMut<'a, T>>);
impl<T> Tree<T> {
pub fn iter_mut(&mut self) -> IterMut<T> {
let mut deque = VecDeque::new();
self.root.as_mut().map(|root| deque.push_front(root.iter_mut()));
IterMut(deque)
}
}
// round-trip through a raw pointer to unbound the lifetime from
// ourselves
Some(&mut *(elem as *mut _))
impl<T> Node<T> {
pub fn iter_mut(&mut self) -> NodeIterMut<T> {
NodeIterMut {
elem: Some(&mut self.elem),
left: self.left.as_mut().map(|node| &mut **node),
right: self.right.as_mut().map(|node| &mut **node),
}
}
}
impl<'a, T> Iterator for NodeIterMut<'a, T> {
type Item = State<'a, T>;
fn next(&mut self) -> Option<Self::Item> {
match self.left.take() {
Some(node) => Some(State::Node(node)),
None => match self.elem.take() {
Some(elem) => Some(State::Elem(elem)),
None => match self.right.take() {
Some(node) => Some(State::Node(node)),
None => None,
}
}
}
}
}
impl<'a, T> DoubleEndedIterator for NodeIterMut<'a, T> {
fn next_back(&mut self) -> Option<Self::Item> {
match self.right.take() {
Some(node) => Some(State::Node(node)),
None => match self.elem.take() {
Some(elem) => Some(State::Elem(elem)),
None => match self.left.take() {
Some(node) => Some(State::Node(node)),
None => None,
}
}
}
}
}
impl<'a, T> Iterator for IterMut<'a, T> {
type Item = &'a mut T;
fn next(&mut self) -> Option<Self::Item> {
loop {
match self.0.front_mut().and_then(|node_it| node_it.next()) {
Some(State::Elem(elem)) => return Some(elem),
Some(State::Node(node)) => self.0.push_front(node.iter_mut()),
None => if let None = self.0.pop_front() { return None },
}
}
}
}
impl<'a, T> DoubleEndedIterator for IterMut<'a, T> {
fn next(&mut self) -> Option<Self::Item> {
loop {
match self.0.back_mut().and_then(|node_it| node_it.next_back()) {
Some(State::Elem(elem)) => return Some(elem),
Some(State::Node(node)) => self.0.push_back(node.iter_mut()),
None => if let None = self.0.pop_back() { return None },
}
}
}
}
```
A very subtle but interesting detail in this design is that it *relies on
privacy to be sound*. Borrowck works on some very simple rules. One of those rules
is that if we have a live &mut Foo and Foo contains an &mut Bar, then that &mut
Bar is *also* live. Since IterMut is always live when `next` can be called, if
`ring` were public then we could mutate `ring` while outstanding mutable borrows
to it exist!
All of these are completely safe and work on stable Rust! This ultimately
falls out of the simple struct case we saw before: Rust understands that you
can safely split a mutable reference into subfields. We can then encode
permanently consuming a reference via Options (or in the case of slices,
replacing with an empty slice).

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