22 KiB
SeqCst
SeqCst
is probably the most interesting ordering, because it is simultaneously
the simplest and most complex atomic memory ordering in existence. It’s
simple, because if you do only use SeqCst
everywhere then you can kind of
maybe pretend like the Abstract Machine has a concept of time; phrases like
“latest value” make sense, the program can be thought of as a set of steps that
interleave, there is a universal “now” and “before” and wouldn’t that be nice?
But it’s also the most complex, because as soon as look under the hood you
realize just how incredibly convoluted and hard to follow the actual rules
behind it are, and it gets really ugly really fast as soon as you try to mix it
with any other ordering.
To understand SeqCst
, we first have to understand the problem it exists to
solve. The first complexity is that this problem can only be observed in the
presence of at least four different threads and two separate atomic variables;
anything less and it’s not possible to notice a difference. The common example
used to show where weaker orderings produce counterintuitive results is this:
# use std::sync::atomic::{self, AtomicBool};
use std::thread;
// Set this to Relaxed, Acquire, Release, AcqRel, doesn’t matter — the result is
// the same (modulo panics caused by attempting acquire stores or release
// loads).
const ORDERING: atomic::Ordering = atomic::Ordering::Relaxed;
static X: AtomicBool = AtomicBool::new(false);
static Y: AtomicBool = AtomicBool::new(false);
let a = thread::spawn(|| { X.store(true, ORDERING) });
let b = thread::spawn(|| { Y.store(true, ORDERING) });
let c = thread::spawn(|| { while !X.load(ORDERING) {} Y.load(ORDERING) });
let d = thread::spawn(|| { while !Y.load(ORDERING) {} X.load(ORDERING) });
let a = a.join().unwrap();
let b = b.join().unwrap();
let c = c.join().unwrap();
let d = d.join().unwrap();
# return;
// This assert is allowed to fail.
assert!(c || d);
The basic setup of this code, for all of its possible executions, looks like this:
a static X c d static Y b
╭─────────╮ ┌───────┐ ╭─────────╮ ╭─────────╮ ┌───────┐ ╭─────────╮
│ store X ├─┐ │ false │ ┌─┤ load X │ │ load Y ├─┐ │ false │ ┌─┤ store Y │
╰─────────╯ │ └───────┘ │ ╰────╥────╯ ╰────╥────╯ │ └───────┘ │ ╰─────────╯
└─┬───────┐ │ ╭────⇓────╮ ╭────⇓────╮ │ ┌───────┬─┘
│ true ├─┘ │ load Y ├─? ?─┤ load X │ └─┤ true │
└───────┘ ╰─────────╯ ╰─────────╯ └───────┘
In other words, a
and b
are guaranteed to, at some point, store true
into
X
and Y
respectively, and c
and d
are guaranteed to, at some point, load
those values of true
from X
and Y
(there could also be an arbitrary number
of loads of false
by c
and d
, but they’ve been omitted since they don’t
actually affect the execution at all). The question now is when c
and d
load
from Y
and X
respectively, is it possible for them both to load false
?
And looking at this diagram, there’s absolutely no reason why not. There isn’t even a single arrow connecting the left and right hand sides so far, so the load has no coherence-based restrictions on which value it is allowed to pick — and this goes for both sides equally, so we could end up with an execution like this:
a static X c d static Y b
╭─────────╮ ┌───────┐ ╭─────────╮ ╭─────────╮ ┌───────┐ ╭─────────╮
│ store X ├─┐ │ false ├┐ ┌┤ load X │ │ load Y ├┐ ┌┤ false │ ┌─┤ store Y │
╰─────────╯ │ └───────┘│ │╰────╥────╯ ╰────╥────╯│ │└───────┘ │ ╰─────────╯
└─┬───────┐└─│─────║──────┐┌─────║─────│─┘┌───────┬─┘
│ true ├──┘╭────⇓────╮┌─┘╭────⇓────╮└──┤ true │
└───────┘ │ load Y ├┘└─┤ load X │ └───────┘
╰─────────╯ ╰─────────╯
Which results in a failed assert. This execution is brought about because the
model of separate modification orders means that there is no relative ordering
between X
and Y
being changed, and so each thread is allowed to “see” either
order. However, some algorithms will require a globally agreed-upon ordering,
and this is where SeqCst
can come in useful.
This ordering, first and foremost, inherits the guarantees from all the other
orderings — it is an acquire operation for loads, a release operation for stores
and an acquire-release operation for RMWs. In addition to this, it gives some
guarantees unique to SeqCst
about what values it is allowed to load. Note that
these guarantees are not about preventing data races: unless you have some
unrelated code that triggers a data race given an unexpected condition, using
SeqCst
can only prevent you from race conditions because its guarantees only
apply to other SeqCst
operations rather than all data accesses.
S
SeqCst
is fundamentally about S, which is the global ordering of all
SeqCst
operations in an execution of the program. It is consistent between
every atomic and every thread, and all stores, fences and RMWs that use a
sequentially consistent ordering have a place in it (but no other operations
do). It is in contrast to modification orders, which are similarly total but
only scoped to a single atomic rather than the whole program.
Other than an edge case involving SeqCst
mixed with weaker orderings (detailed
later on), S is primarily controlled by the happens-before relations in a
program: this means that if an action A happens-before an action B, it is
also guaranteed to appear before B in S. Other than that restriction, S is
unspecified and will be chosen arbitrarily during execution.
Once a particular S has been established, every atomic’s modification order is
then guaranteed to be consistent with it, so a SeqCst
load will never see a
value that has been overwritten by a write that occurred before it in S, or a
value that has been written by a write that occured after it in S (note that a
Relaxed
/Acquire
load however might, since there is no “before” or “after” as
it is not in S in the first place).
More formally, this guarantee can be described with coherence orderings, a relation which expresses which of two operations appears before the other in an atomic’s modification order. It is said that an operation A is coherence-ordered-before another operation B if any of the following conditions are met:
- A is a store or RMW, B is a store or RMW, and A appears before B in the modification order.
- A is a store or RMW, B is a load, and B reads the value stored by A.
- A is a load, B is a store or RMW, and A takes its value from a place in the modification order that appears before B.
- A is coherence-ordered-before a different operation X, and X is coherence-ordered-before B (the basic transitivity property).
The following diagram gives examples for the main three rules (in each case A is coherence-ordered-before B):
Rule 1 ┃ Rule 2 ┃ Rule 3
┃ ┃
╭───╮ ┌─┬───┐ ╭───╮ ┃ ╭───╮ ┌─┬───┐ ╭───╮ ┃ ╭───╮ ┌───┐ ╭───╮
│ A ├─┘ │ │ ┌─┤ B │ ┃ │ A ├─┘ │ ├───┤ B │ ┃ │ A ├───┤ │ ┌─┤ B │
╰───╯ └───┘ │ ╰───╯ ┃ ╰───╯ └───┘ ╰───╯ ┃ ╰───╯ └───┘ │ ╰───╯
┌───┬─┘ ┃ ┃ ┌───┬─┘
│ │ ┃ ┃ │ │
└───┘ ┃ ┃ └───┘
The only important thing to note is that for two loads of the same value in the modification order, neither is coherence-ordered-before the other, as in the following example where A has no coherence ordering relation to B:
╭───╮ ┌───┐ ╭───╮
│ A ├───┤ ├───┤ B │
╰───╯ └───┘ ╰───╯
With this terminology applied, we can use a more precise definition of
SeqCst
’s guarantee: for two SeqCst
operations on the same atomic A and
B, where A precedes B in S, either A must be coherence-ordered-before
B or they must both be loads that see the same value in the modification
order. Effectively, this one rule ensures that S’s order “propagates”
throughout all the atomics of the program — you can imagine each operation in
S as storing a snapshot of the world, so that every subsequent operation is
consistent with it.
Applying SeqCst
So, looking back at our program, let’s consider how we could use SeqCst
to
make that execution invalid. As a refresher, here’s the framework for every
possible execution of the program:
a static X c d static Y b
╭─────────╮ ┌───────┐ ╭─────────╮ ╭─────────╮ ┌───────┐ ╭─────────╮
│ store X ├─┐ │ false │ ┌─┤ load X │ │ load Y ├─┐ │ false │ ┌─┤ store Y │
╰─────────╯ │ └───────┘ │ ╰────╥────╯ ╰────╥────╯ │ └───────┘ │ ╰─────────╯
└─┬───────┐ │ ╭────⇓────╮ ╭────⇓────╮ │ ┌───────┬─┘
│ true ├─┘ │ load Y ├─? ?─┤ load X │ └─┤ true │
└───────┘ ╰─────────╯ ╰─────────╯ └───────┘
First of all, both the final loads (c
and d
’s second operations) need to
become SeqCst
, because they need to be aware of the total ordering that
determines whether X
or Y
becomes true
first. And secondly, we need to
establish that ordering in the first place, and that needs to be done by making
sure that there is always one operation in S that both sees one of the atomics
as true
and precedes both final loads in S, so that the coherence ordering
guarantee will apply (the final loads themselves don’t work for this since
although they “know” that their corresponding atomic is true
they don’t
interact with it directly so S doesn’t care).
There are two operations in the program that could fulfill the first condition,
should they be made SeqCst
: the stores of true
and the first loads. However,
the second condition ends up ruling out using the stores, since in order to make
sure that they precede the final loads in S it would be necessary to have the
first loads be SeqCst
anyway (due to the mixed-SeqCst
special case detailed
later), so in the end we can just leave them as Relaxed
.
This leaves us with the correct version of the above program, which is guaranteed to never panic:
# use std::sync::atomic::{AtomicBool, Ordering::{Relaxed, SeqCst}};
use std::thread;
static X: AtomicBool = AtomicBool::new(false);
static Y: AtomicBool = AtomicBool::new(false);
let a = thread::spawn(|| { X.store(true, Relaxed) });
let b = thread::spawn(|| { Y.store(true, Relaxed) });
let c = thread::spawn(|| { while !X.load(SeqCst) {} Y.load(SeqCst) });
let d = thread::spawn(|| { while !Y.load(SeqCst) {} X.load(SeqCst) });
let a = a.join().unwrap();
let b = b.join().unwrap();
let c = c.join().unwrap();
let d = d.join().unwrap();
// This assert is **not** allowed to fail.
assert!(c || d);
As there are four SeqCst
operations with a partial order between two pairs in
them (caused by the sequenced before relation), there are six possible
executions of this program:
- All of
c
’s loads preceded
’s loads:c
loadsX
(givestrue
)c
loadsY
(gives eitherfalse
ortrue
)d
loadsY
(givestrue
)d
loadsX
(required to betrue
)
- Both initial loads precede both final loads:
c
loadsX
(givestrue
)d
loadsY
(givestrue
)c
loadsY
(required to betrue
)d
loadsX
(required to betrue
)
- As above, but the final loads occur in a different order:
c
loadsX
(givestrue
)d
loadsY
(givestrue
)d
loadsX
(required to betrue
)c
loadsY
(required to betrue
)
- As before, but the initial loads occur in a different order:
d
loadsY
(givestrue
)c
loadsX
(givestrue
)c
loadsY
(required to betrue
)d
loadsX
(required to betrue
)
- As above, but the final loads occur in a different order:
d
loadsY
(givestrue
)c
loadsX
(givestrue
)d
loadsX
(required to betrue
)c
loadsY
(required to betrue
)
- All of
d
’s loads precedec
’s loads:d
loadsY
(givestrue
)d
loadsX
(gives eitherfalse
ortrue
)c
loadsX
(givestrue
)c
loadsY
(required to betrue
)
All the places where the load was required to give true
were caused by a
preceding load in S of the same atomic which saw true
— otherwise, the load
would be coherence-ordered-before a load which precedes it in S, and that is
impossible.
The mixed-SeqCst
special case
As I’ve been alluding to for a while, I wasn’t being totally truthful when I said that S is consistent with happens-before relations — in reality, it is only consistent with strongly happens-before relations, which presents a subtly-defined subset of happens-before relations. In particular, it excludes two situations:
- The
SeqCst
operation A synchronizes-with anAcquire
orAcqRel
operation B which is sequenced before anotherSeqCst
operation C. Here, despite the fact that A happens-before C, A does not strongly happen-before C and so is there not guaranteed to precede C in S. - The
SeqCst
operation A is sequenced-before theRelease
orAcqRel
operation B, which synchronizes-with anotherSeqCst
operation C. Similarly, despite the fact that A happens-before C, A might not precede C in S.
The first situation is illustrated below, with SeqCst
accesses repesented with
asterisks:
t_1 x t_2
╭─────╮ ┌─↘───┐ ╭─────╮
│ *A* ├─┘ │ 1 ├───→ B │
╰─────╯ └───┘ ╰──╥──╯
╭──⇓──╮
│ *C* │
╰─────╯
A happens-before, but does not strongly happen-before, C — and anything sequenced after C will have the same treatment (unless more synchronization is used). This means that C is actually allowed to precede A in S, despite conceptually occuring after it. However, anything sequenced before A, because there is at least one sequence on either side of the synchronization, will strongly happen-before C.
But this is all highly theoretical at the moment, so let’s make an example to
show how that rule can actually affect the execution of code. So, if C were to
precede A in S (and they are not both loads) then that means C is always
coherence-ordered-before A. Let’s say then that C loads from x
(the atomic
that A has to access), it may load the value that came before A if it were to
precede A in S:
t_1 x t_2
╭─────╮ ┌───┐ ╭─────╮
│ *A* ├─┐ │ 0 ├─┐┌→ B │
╰─────╯ │ └───┘ ││╰──╥──╯
└─↘───┐┌─┘╭──⇓──╮
│ 1 ├┘└─→ *C* │
└───┘ ╰─────╯
Ah wait no, that doesn’t work because regular coherence still mandates that 1
is the only value that can be loaded. In fact, once 1
is loaded S’s required
consistency with coherence orderings means that A is required to precede C in
S after all.
So somehow, to observe this difference we need to have a different SeqCst
operation, let’s call it E, be the one that loads from x
, where C is
guaranteed to precede it in S (so we can observe the “weird” state in between
C and A) but C also doesn’t happen-before it (to avoid coherence getting in the
way) — and to do that, all we have to do is have C appear before a SeqCst
operation D in the modification order of another atomic, but have D be a store
so as to avoid C synchronizing with it, and then our desired load E can simply
be sequenced after D (this will carry over the “precedes in S” guarantee, but
does not restore the happens-after relation to C since that was already dropped
by having D be a store).
In diagram form, that looks like this:
t_1 x t_2 helper t_3
╭─────╮ ┌───┐ ╭─────╮ ┌─────┐ ╭─────╮
│ *A* ├─┐ │ 0 ├┐┌─→ B │ ┌─┤ 0 │ ┌─┤ *D* │
╰─────╯ │ └───┘││ ╰──╥──╯ │ └─────┘ │ ╰──╥──╯
│ └│────║────│─────────│┐ ║
└─↘───┐ │ ╭──⇓──╮ │ ┌─────↙─┘│╭──⇓──╮
│ 1 ├─┘ │ *C* ←─┘ │ 1 │ └→ *E* │
└───┘ ╰─────╯ └─────┘ ╰─────╯
S = C → D → E → A
C is guaranteed to precede D in S, and D is guaranteed to precede E, but
because this exception means that A is not guaranteed to precede C, it is
totally possible for it to come at the end, resulting in the surprising but
totally valid outcome of E loading 0
from x
. In code, this can be expressed
as the following code not being guaranteed to panic:
# use std::sync::atomic::{AtomicU8, Ordering::{Acquire, SeqCst}};
# return;
static X: AtomicU8 = AtomicU8::new(0);
static HELPER: AtomicU8 = AtomicU8::new(0);
// thread_1
X.store(1, SeqCst); // A
// thread_2
assert_eq!(X.load(Acquire), 1); // B
assert_eq!(HELPER.load(SeqCst), 0); // C
// thread_3
HELPER.store(1, SeqCst); // D
assert_eq!(X.load(SeqCst), 0); // E
The second situation listed above has very similar consequences. Its abstract form is the following execution in which A is not guaranteed to precede C in S, despite A happening-before C:
t_1 x t_2
╭─────╮ ┌─↘───┐ ╭─────╮
│ *A* │ │ │ 0 ├───→ *C* │
╰──╥──╯ │ └───┘ ╰─────╯
╭──⇓──╮ │
│ B ├─┘
╰─────╯
Similarly to before, we can’t just have A access x
to show why A not
necessarily preceding C in S matters; instead, we have to introduce a second
atomic and third thread to break the happens-before chain first. And finally, a
single relaxed load F at the end is added just to prove that the weird execution
actually happened (leaving x
as 2 instead of 1).
t_3 helper t_1 x t_2
╭─────╮ ┌─────┐ ╭─────╮ ┌───┐ ╭─────╮
│ *D* ├┐┌─┤ 0 │ ┌─┤ *A* │ │ 0 │ ┌─→ *C* │
╰──╥──╯││ └─────┘ │ ╰──╥──╯ └───┘ │ ╰──╥──╯
║ └│─────────│────║─────┐ │ ║
╭──⇓──╮ │ ┌─────↙─┘ ╭──⇓──╮ ┌─↘───┐ │ ╭──⇓──╮
│ *E* ←─┘ │ 1 │ │ B ├─┘││ 1 ├─┘┌┤ F │
╰─────╯ └─────┘ ╰─────╯ │└───┘ │╰─────╯
└↘───┐ │
│ 2 ├──┘
└───┘
S = C → D → E → A
This execution mandates both C preceding A in S and A happening-before C,
something that is only possible through these two mixed-SeqCst
special
exceptions. It can be expressed in code as well:
# use std::sync::atomic::{AtomicU8, Ordering::{Release, Relaxed, SeqCst}};
# return;
static X: AtomicU8 = AtomicU8::new(0);
static HELPER: AtomicU8 = AtomicU8::new(0);
// thread_3
X.store(2, SeqCst); // D
assert_eq!(HELPER.load(SeqCst), 0); // E
// thread_1
HELPER.store(1, SeqCst); // A
X.store(1, Release); // B
// thread_2
assert_eq!(X.load(SeqCst), 1); // C
assert_eq!(X.load(Relaxed), 2); // F
If this seems ridiculously specific and obscure, that’s because it is. Originally, back in C++11, this special case didn’t exist — but then six years later it was discovered that in practice atomics on Power, Nvidia GPUs and sometimes ARMv7 would have this special case, and fixing the implementations would make atomics significantly slower. So instead, in C++20 they simply encoded it into the specification.
Generally however, this rule is so complex it’s best to just avoid it entirely
by never mixing SeqCst
and non-SeqCst
on a single atomic in the first place.