1.9 KiB
% Checked Uninitialized Memory
Like C, all stack variables in Rust are uninitialized until a value is explicitly assigned to them. Unlike C, Rust statically prevents you from ever reading them until you do:
fn main() {
let x: i32;
println!("{}", x);
}
src/main.rs:3:20: 3:21 error: use of possibly uninitialized variable: `x`
src/main.rs:3 println!("{}", x);
^
This is based off of a basic branch analysis: every branch must assign a value
to x
before it is first used. Interestingly, Rust doesn't require the variable
to be mutable to perform a delayed initialization if every branch assigns
exactly once. However the analysis does not take advantage of constant analysis
or anything like that. So this compiles:
fn main() {
let x: i32;
if true {
x = 1;
} else {
x = 2;
}
println!("{}", x);
}
but this doesn't:
fn main() {
let x: i32;
if true {
x = 1;
}
println!("{}", x);
}
src/main.rs:6:17: 6:18 error: use of possibly uninitialized variable: `x`
src/main.rs:6 println!("{}", x);
while this does:
fn main() {
let x: i32;
if true {
x = 1;
println!("{}", x);
}
// Don't care that there are branches where it's not initialized
// since we don't use the value in those branches
}
If a value is moved out of a variable, that variable becomes logically uninitialized if the type of the value isn't Copy. That is:
fn main() {
let x = 0;
let y = Box::new(0);
let z1 = x; // x is still valid because i32 is Copy
let z2 = y; // y is now logically uninitialized because Box isn't Copy
}
However reassigning y
in this example would require y
to be marked as
mutable, as a Safe Rust program could observe that the value of y
changed.
Otherwise the variable is exactly like new.